powershell - 如何获取当前的PowerShell执行文件？

注意:PowerShell 1.0
我想获取当前正在执行的PowerShell文件名。也就是说，如果我像这样开始 session :

powershell.exe .\myfile.ps1

我想获取字符串“。\ myfile.ps1” (或类似名称)。 编辑:“myfile.ps1”首选。
有任何想法吗？

最佳答案

我尝试在此处总结各种答案，这些答案针对PowerShell 5进行了更新:

如果您仅使用PowerShell 3或更高版本，请使用$PSCommandPath

如果要与旧版本兼容，请插入垫片:if ($PSCommandPath -eq $null) { function GetPSCommandPath() { return $MyInvocation.PSCommandPath; } $PSCommandPath = GetPSCommandPath; }如果$PSCommandPath不存在，则会添加它。
尽管$PSCommandPath变量受常规作用域规则的约束，但可以在任何位置(顶级或函数内部)执行填充程序代码(例如，将填充程序放入函数中，该变量仅作用于该函数)。

细节
在各种答案中使用了4种不同的方法，因此我编写了此脚本来演示每种方法(以及$PSCommandPath):

function PSCommandPath() { return $PSCommandPath; }
function ScriptName() { return $MyInvocation.ScriptName; }
function MyCommandName() { return $MyInvocation.MyCommand.Name; }
function MyCommandDefinition() {
    # Begin of MyCommandDefinition()
    # Note: ouput of this script shows the contents of this function, not the execution result
    return $MyInvocation.MyCommand.Definition;
    # End of MyCommandDefinition()
}
function MyInvocationPSCommandPath() { return $MyInvocation.PSCommandPath; }

Write-Host "";
Write-Host "PSVersion: $($PSVersionTable.PSVersion)";
Write-Host "";
Write-Host "`$PSCommandPath:";
Write-Host " *   Direct: $PSCommandPath";
Write-Host " * Function: $(ScriptName)";
Write-Host "";
Write-Host "`$MyInvocation.ScriptName:";
Write-Host " *   Direct: $($MyInvocation.ScriptName)";
Write-Host " * Function: $(ScriptName)";
Write-Host "";
Write-Host "`$MyInvocation.MyCommand.Name:";
Write-Host " *   Direct: $($MyInvocation.MyCommand.Name)";
Write-Host " * Function: $(MyCommandName)";
Write-Host "";
Write-Host "`$MyInvocation.MyCommand.Definition:";
Write-Host " *   Direct: $($MyInvocation.MyCommand.Definition)";
Write-Host " * Function: $(MyCommandDefinition)";
Write-Host "";
Write-Host "`$MyInvocation.PSCommandPath:";
Write-Host " *   Direct: $($MyInvocation.PSCommandPath)";
Write-Host " * Function: $(MyInvocationPSCommandPath)";
Write-Host "";

输出:

PS C:\> .\Test\test.ps1

PSVersion: 5.1.19035.1

$PSCommandPath:
 *   Direct: C:\Test\test.ps1
 * Function: C:\Test\test.ps1

$MyInvocation.ScriptName:
 *   Direct:
 * Function: C:\Test\test.ps1

$MyInvocation.MyCommand.Name:
 *   Direct: test.ps1
 * Function: MyCommandName

$MyInvocation.MyCommand.Definition:
 *   Direct: C:\Test\test.ps1
 * Function:
    # Begin of MyCommandDefinition()
    # Note this is the contents of the MyCommandDefinition() function, not the execution results
    return $MyInvocation.MyCommand.Definition;
    # End of MyCommandDefinition()


$MyInvocation.PSCommandPath:
 *   Direct:
 * Function: C:\Test\test.ps1

笔记:

从C:\执行，但是实际脚本是C:\Test\test.ps1。

没有方法告诉您传递的调用路径(.\Test\test.ps1)

$PSCommandPath是唯一可靠的方法，但已在PowerShell 3中引入

对于3之前的版本，在

函数内部和外部都无法使用单个方法

关于powershell - 如何获取当前的PowerShell执行文件？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/817198/