我有以下查询
SELECT
interview_content.title `title`,
gallery_images.img_path img
FROM
`interview`,
`interview_content`,
`gallery`,
`gallery_images`
WHERE
`gallery_images`.`id_parrent` = `gallery`.`id`
AND
`gallery`.`id` = `interview`.`gallery_id`
AND
`gallery_images`.`default` = '1'
AND
`interview`.`id` = `interview_content`.`id_parrent`
AND
interview_content.id_lang = '2'
ORDER BY
interview.date DESC
我需要在
gallery
,gallery_images
表上使用LEFT JOIN(即使没有画廊或默认图像也要获得interview.title
)非常感谢
更新
问题出在第二左联接中。我无法让他们正确合作。当我尝试
SELECT
interview_content.title `title`,
gi.img_path img
FROM
`interview`,
`interview_content`
LEFT JOIN `gallery` as g ON g.`id` = `interview`.`gallery_id`
LEFT JOIN `gallery_images` as gi ON gi.id_parrent = g.`id`
WHERE
`interview`.`id` = `interview_content`.`id_parrent`
AND
interview_content.id_lang = '2'
ORDER BY
interview.date DESC
it returns //Unknown column 'interview.gallery_id' in 'on clause'
最佳答案
你知道你需要做什么。
Google是您的朋友吗?
http://en.wikipedia.org/wiki/Join_%28SQL%29#Left_outer_join
关于php - 如何在此查询中使用LEFT JOIN,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/5020074/