我有一个绘制树的类,但是我希望能够在按下鼠标时绘制另一棵树,但是我目前不能作为redraw()使用;只需在当前画布上添加一棵树即可。我希望每次单击都能绘制一棵新树。
我试图找到一种删除对象或重置类属性的方法,但是我没有成功。我已经使用了p5.js编辑器,并且下面的代码可以在这里找到:https://editor.p5js.org/remcqueen/sketches/Sk0smd8G4
var a;
function setup() {
createCanvas(600, 600);
a = new clCreateTree();
}
function draw() {
noLoop();
background(220);
a.draw();
}
function mousePressed() {
redraw();
}
class clCreateTree {
constructor() {
this.tree = createGraphics(width, height);
this.n = 0;
this.leafs = [];
this.treeHeight = 150;
this.treeDensity = 3;
this.treeAge = 70;
}
sketch() {
this.tree.beginShape();
this.tree.noStroke();
this.tree.background(0, 0);
for (var i = 0; i < this.treeDensity; i++) {
this.tree.fill(map(i, 0, 2, 60, 20));
this.branch(width/2, height, this.treeAge, -HALF_PI, this.treeHeight, 0);
}
this.tree.endShape();
}
draw() {
this.sketch();
image(this.tree, 5, 5);
}
branch(x, y, bSize, theta, bLength, pos) {
this.n += 0.01;
var diam = lerp(bSize, 0.7 * bSize, pos / bLength);
diam *= map(noise(this.n), 0, 1, 0.4, 1.6);
this.tree.ellipse(x, y, diam, diam);
if (bSize > 0.6) {
if (pos < bLength) {
x += cos(theta + random(-PI / 10, PI / 10));
y += sin(theta + random(-PI / 10, PI / 10));
this.branch(x, y, bSize, theta, bLength, pos + 1);
} else {
this.leafs.push(createVector(x, y));
var drawLeftBranch = random(1) > 0.1;
var drawRightBranch = random(1) > 0.1;
if (drawLeftBranch) this.branch(x, y, random(0.5, 0.7) * bSize, theta - random(PI / 15, PI / 5), random(0.6, 0.8) * bLength, 0);
if (drawRightBranch) this.branch(x, y, random(0.5, 0.7) * bSize, theta + random(PI / 15, PI / 5), random(0.6, 0.8) * bLength, 0);
if (!drawLeftBranch && !drawRightBranch) {
this.tree.push()
this.tree.translate(x, y);
this.tree.rotate(theta);
this.tree.quad(0, -diam / 2, 2 * diam, -diam / 6, 2 * diam, diam / 6, 0, diam / 2);
this.tree.pop();
}
}
}
}
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/p5.js/0.6.1/p5.js"></script>
预期的结果应该是,当按下鼠标时,将绘制一棵新树,而不会出现当前发生的任何重叠。
最佳答案
绘制树之前,必须先clear()
graphics object:
sketch() {
this.tree.beginShape();
this.tree.clear(); // <--- clear
this.tree.noStroke();
for (var i = 0; i < this.treeDensity; i++) {
this.tree.fill(map(i, 0, 2, 60, 20));
this.branch(width/2, height, this.treeAge, -HALF_PI, this.treeHeight, 0);
}
this.tree.endShape();
}
或者您必须在绘制树之前绘制纯色背景(alpha = 255):
sketch() {
this.tree.beginShape();
this.tree.noStroke();
this.tree.background(255,255);
for (var i = 0; i < this.treeDensity; i++) {
this.tree.fill(map(i, 0, 2, 60, 20));
this.branch(width/2, height, this.treeAge, -HALF_PI, this.treeHeight, 0);
}
this.tree.endShape();
}
var a;
function setup() {
createCanvas(600, 600);
a = new clCreateTree();
}
function draw() {
noLoop();
background(220);
a.draw();
}
function mousePressed() {
redraw();
}
class clCreateTree {
constructor() {
this.tree = createGraphics(width, height);
this.n = 0;
this.leafs = [];
this.treeHeight = 150;
this.treeDensity = 3;
this.treeAge = 70;
}
sketch() {
this.tree.beginShape();
this.tree.clear();
this.tree.noStroke();
for (var i = 0; i < this.treeDensity; i++) {
this.tree.fill(map(i, 0, 2, 60, 20));
this.branch(width/2, height, this.treeAge, -HALF_PI, this.treeHeight, 0);
}
this.tree.endShape();
}
draw() {
this.sketch();
image(this.tree, 5, 5);
}
branch(x, y, bSize, theta, bLength, pos) {
this.n += 0.01;
var diam = lerp(bSize, 0.7 * bSize, pos / bLength);
diam *= map(noise(this.n), 0, 1, 0.4, 1.6);
this.tree.ellipse(x, y, diam, diam);
if (bSize > 0.6) {
if (pos < bLength) {
x += cos(theta + random(-PI / 10, PI / 10));
y += sin(theta + random(-PI / 10, PI / 10));
this.branch(x, y, bSize, theta, bLength, pos + 1);
} else {
this.leafs.push(createVector(x, y));
var drawLeftBranch = random(1) > 0.1;
var drawRightBranch = random(1) > 0.1;
if (drawLeftBranch) this.branch(x, y, random(0.5, 0.7) * bSize, theta - random(PI / 15, PI / 5), random(0.6, 0.8) * bLength, 0);
if (drawRightBranch) this.branch(x, y, random(0.5, 0.7) * bSize, theta + random(PI / 15, PI / 5), random(0.6, 0.8) * bLength, 0);
if (!drawLeftBranch && !drawRightBranch) {
this.tree.push()
this.tree.translate(x, y);
this.tree.rotate(theta);
this.tree.quad(0, -diam / 2, 2 * diam, -diam / 6, 2 * diam, diam / 6, 0, diam / 2);
this.tree.pop();
}
}
}
}
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/p5.js/0.6.1/p5.js"></script>
关于javascript - 如何重绘从p5.js javascript中的类创建的对象,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/54153201/