我正在使用C编写以下代码。到目前为止,所有代码都可以正常工作,并且可以缩放到正确的水平,依此类推,但是我一直在努力使颜色按我的意愿工作。理想情况下,无论颜色如何,我都希望得到这样的结果:
但是我的程序如下所示,目前产生的是这样的:
因此,我希望我能根据需要提供任何帮助,使颜色变成事实。
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#define ITERMAX 100.0
#define DIVERGING 1.1
#define XMAX 500
#define YMAX 500
#define COLORINTENSITY 255
/* allow up to ITERMAX feedbacks searching for convergence
for the feedback
z0 = 0 + 0i
znew = z^2 + c
If we have not diverged to distance DIVERGING before ITERMAX feedbacks
we will assume the feedback is convergent at this value of c.
We will report divergence if |z|^2 > DIVERGING
*/
/* We will print color values for each pixel from (0, 0) to (XMAX, YMAX)
The color of pixel (cx, cy) will be set by convergent()
or by divergent()
depending on the convergence or divergence of the feedback
when c = cx + icy
*/
/* The max value of the red, green, or blue component of a color */
void convergent(); /* one color for convergence */
void divergent(); /* a different color for divergence */
void feedback(double *x, double *y, double cx, double cy);
void pixel(char red, char green, char blue);
FILE *fp;
int main()
{
fp = fopen("mandelbrot.ppm", "wb");
double x, y, cx, cy;
int iteration,squarex, squarey, pixelx, pixely;
double grow=1.0;
/* header for PPM output */
fprintf(fp, "P6\n# CREATOR: EK, BB, RPJ via the mandel program\n");
fprintf(fp, "%d %d\n%d\n",XMAX, YMAX, COLORINTENSITY);
for (pixely = 0; pixely < YMAX; pixely++) {
for (pixelx = 0; pixelx < XMAX; pixelx++) {
cx = (((float)pixelx)/((float)XMAX)-0.5)/grow*3.0-0.7;
cy = (((float)pixely)/((float)YMAX)-0.5)/grow*3.0;
x = 0.0; y = 0.0;
for (iteration=1;iteration<ITERMAX;iteration++) {
feedback(&x, &y, cx, cy);
if (x*x + y*y > 100.0) iteration = 1000;
}
if (iteration==ITERMAX) {
iteration = x*x + y*y;
pixel((char) 0, (char) 0, (char) 0);
}
else {
iteration = sqrt(x*x + y*y);
pixel((char) iteration, (char) 0, (char) iteration);
}
}
}
}
void feedback(double *x, double *y, double cx, double cy) {
/* Update x and y according to the feedback equation
xnew = x^2 - y^2 + cx
ynew = 2xy + cy
(these are the real and imaginary parts of the complex equation:
znew = z^2 + c)
*/
double xnew = (*x) * (*x) - (*y) * (*y) + cx;
double ynew = 2 * *x * *y + cy;
*x = xnew;
*y = ynew;
}
void pixel(char red, char green, char blue) {
/* put a r-g-b triple to the standard out */
fputc(red, fp);
fputc(green, fp);
fputc(blue, fp);
}
最佳答案
要修复此带区,您需要遍历表以找到迭代次数的最大值,然后将其他值缩放为相对于该最大值的值(即标准化值)。您可能还希望对数值重新缩放以调整颜色变化的斜率。
而且您可能不想直接在RGB空间中工作。如果在HSB空间中定义颜色,则可以设置恒定的色相和饱和度,并根据标准化的迭代计数成比例地改变亮度。
关于C Mandelbrot套装着色,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/36991937/