我有如下的Hibernate配置。

CPU型号:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
  <class name="org.example.CPUModel" table="cpu_model">
    <id name="cpuModelId" type="java.lang.Integer" unsaved-value="null">
      <column name="cpu_model_id"/>
      <generator class="identity"/>
    </id>
    <property name="name" type="java.lang.String">
      <column length="32" name="name"/>
    </property>
    <set name="softwares" inverse="true" lazy="false" table="cpu_model_software" cascade="all-delete-orphan" order-by="cpu_sw_id desc">
      <key>
        <column name="cpu_model_id" not-null="true"/>
      </key>
      <one-to-many class="org.example.CPUModelSoftware"/>
    </set>
  </class>
</hibernate-mapping>


CPU型号软件

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
  <class name="org.example.CPUModelSoftware" table="cpu_model_software">
    <composite-id name="cpuModelSoftwarePK" class="org.example.CPUModelSoftwarePK">
      <key-property name="cpuModelId" column="cpu_model_id" type="java.lang.Integer"/>
      <key-property name="cpuSwId" column="cpu_sw_id" type="java.lang.Integer"/>
    </composite-id>
    <many-to-one class="org.example.CPUSoftware" insert="false" update="false" fetch="select" name="cpuSw">
      <column name="cpu_sw_id" not-null="true"/>
    </many-to-one>
  </class>
</hibernate-mapping>


选择值和更新可以在此配置下正常工作,但插入一个全新的值却不行。

我收到此错误:

DEBUG Could not execute JDBC batch update [insert into exampledb.cpu_model_software (cpu_model_id, cpu_sw_id) values (?, ?)]
java.sql.BatchUpdateException: Column 'cpu_model_id' cannot be null


因此,Hibernate尝试进行插入操作,而无需先从数据库获取生成的cpu_model_id,然后再为CPUModelSoftwarePK对其进行设置(请参阅CPUModel Hibernate配置)。

因此,我该如何告诉Hibernate它首先应该插入cpu_model表。然后从那里获取ID并设置CPUModelSoftwarePK的ID并插入?

CPUModelSoftware / PK的数据库如下。

+----------------+---------+------+-----+---------+-------+
| Field          | Type    | Null | Key | Default | Extra |
+----------------+---------+------+-----+---------+-------+
| cpu_model_id   | int(11) | NO   | MUL | NULL    |       |
| cpu_sw_id      | int(11) | NO   | MUL | NULL    |       |
+----------------+---------+------+-----+---------+-------+


和用于CPUModel

+----------------+------------------+------+-----+---------+----------------+
| Field          | Type             | Null | Key | Default | Extra          |
+----------------+------------------+------+-----+---------+----------------+
| cpu_model_id   | int(11) unsigned | NO   | PRI | NULL    | auto_increment |
| name           | varchar(32)      | NO   |     |         |                |
+----------------+------------------+------+-----+---------+----------------+


编辑

制作新的CPUModelSoftware时,似乎并没有使CPUModelSoftwarePK无效。但是现在我得到这个:

ids for this class must be manually assigned before calling save(): org.example.CPUModelSoftware

最佳答案

据我了解,Hibernate在hbm.xml中定义的映射中不支持派生身份。这意味着Hibernate无法根据cpuModelIdCPUModel之间的关系自动设置CPUModelSoftware的值。

因此,您需要首先保存CPUModel(具有空的softwares),然后需要将其生成的标识符分配给CPUModelSoftware组合ID的字段,然后保存CPUModelSoftware

关于java - hibernate -在另一个类中进行fk自引用时处理添加(插入),我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/6107691/

10-11 20:39