regex - linux通过sed剪切了reg表达模式

我有一个文本文件，我想删除冒号前的字符串。
TXT文件：

jhu-usc.edu_.450.1.lvl-3.TA-LK-A4NW-01A-11D-A34E-05.txt:05556808    0.916496542
jhu-usc.edu_.450.1.lvl-3.TA-LK-A4NW-01A-11D-A34E-05.txt:08883127    0.891518088
jhu-usc.edu_.450.1.lvl-3.TA-LK-A4NW-01A-11D-A34E-05.txt:10537079    0.827900035
jhu-usc.edu_.450.1.lvl-3.TA-LK-A4NW-01A-11D-A34E-05.txt:12497728    0.90517593
jhu-usc.edu_.450.1.lvl-3.TA-LK-A4NW-01A-11D-A34E-05.txt:13195463    NA
jhu-usc.edu_.450.1.lvl-3.TA-LK-A4NW-01A-11D-A34E-05.txt:22240159    0.809459655
jhu-usc.edu_.450.1.lvl-3.TA-LK-A4NW-01A-11D-A34E-05.txt:27050343    NA
jhu-usc.edu_.450.1.lvl-3.TA-LK-A4NY-01A-11D-A34E-05.txt:05556808    0.816581048
jhu-usc.edu_.450.1.lvl-3.TA-LK-A4NY-01A-11D-A34E-05.txt:08883127    0.864387435
jhu-usc.edu_.450.1.lvl-3.TA-LK-A4NY-01A-11D-A34E-05.txt:10537079    0.565236625

期望输出：

5556808 0.916496542
8883127 0.891518088
10537079    0.827900035
12497728    0.90517593
13195463    NA
22240159    0.809459655
27050343    NA
5556808 0.816581048
8883127 0.864387435
10537079    0.565236625

我试过但没成功。

最佳答案

sed

sed 's/^[^:]*://' file.txt

grep

grep -o '[^:]*$' file.txt

awk

awk -F: '{print $2}' file.txt

关于regex - linux通过sed剪切了reg表达模式，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/39221453/