我有以下架构:
我希望可以为两个外键(proposals
和author_id
)调用editor_id
,也可以为单独的键(例如author_proposals
和editor_proposals
)调用User.includes(:proposals)
,并且我需要有延迟或急切加载它们的选项(例如joins
或不加载author_proposals
)。
更新:
#I have the scopes which is like this:
class User < ActiveRecord::Base
has_many :author_proposals, class_name: 'Proposal', foreign_key: :author_id
has_many :editor_proposals, class_name: 'Proposal', foreign_key: :editor_id
end
class Proposal < ActiveRecord::Base
belongs_to :author, class_name: 'User', foreign_key: :author_id
belongs_to :editor, class_name: 'User', foreign_key: :editor_id
end
但我需要一个通用的,它会给我所有的建议(包括
editor_proposals
和has_many
),它也会迫不及待地加载它们。我应该在上使用条件吗? 最佳答案
你可以这样做:
class User < ActiveRecord::Base
has_many :authored_proposals, class_name: 'Proposal', foreign_key: :author_id
has_many :editored_proposals, class_name: 'Proposal', foreign_key: :editor_id
def proposals
authored_proposals | editored_proposals
end
end
class Proposal < ActiveRecord::Base
belongs_to :author, class_name: 'User', foreign_key: :author_id
belongs_to :editor, class_name: 'User', foreign_key: :editor_id
def users
author | editor
end
end
您可以通过执行:
proposals
来紧急加载User.includes(:authored_proposals, :editored_proposals)
。这不是纯铁轨的方式,但似乎更干净的我。您还可以执行以下操作:
class User < ActiveRecord::Base
has_many :authored_proposals, class_name: 'Proposal', foreign_key: :author_id
has_many :editored_proposals, class_name: 'Proposal', foreign_key: :editor_id
has_many : proposals, finder_sql: proc { "SELECT * FROM proposals WHERE (proposals.author_id = #{id} or proposals. editor_id = #{id})" }
end
关于ruby-on-rails - 定义两个外键,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/29560528/