我需要对零件(vechile)的ID数据进行明智的筛选,但它会获取与此相关的所有结果,而不是客户的PID(PID)。我的代码是
我要去哪里错了?

    <?php
   $sql="SELECT DISTINCT(PARTNO) FROM `paidamount` ORDER BY `PARTNO`";
$res=mysql_query($sql);
$num=mysql_num_rows($res);
if($num>0)
{
while($fetch=mysql_fetch_array($res))
{

?>
<tr>
                  <td colspan="15" align="left" style="background-color:#006699;"><p style=" color:#FFFFFF;"><strong><?php echo $fetch['PARTNO']?></strong></p></td>
                      </tr>


        <?php

$sql="SELECT * FROM paidamount where paidamount.PARTNO='".$fetch['PARTNO']."' ORDER BY PARTNO";

//$sql="SELECT * FROM `paidamount`";
                    $result=mysql_query($sql);
                    $numrow=mysql_num_rows($result);

$i=1;
                while($rows=mysql_fetch_array($result))
{
//echo $rows['id'];
 $imid=explode(",",$rows['issued_med']);
   $pmid=explode(",",$rows['ffffff']);

            ?>

最佳答案

更换

 $sql="SELECT DISTINCT(PARTNO) FROM `paidamount` ORDER BY `PARTNO`";


此查询与以下查询:-

 $sql="SELECT DISTINCT(PARTNO) as PARTNO FROM `paidamount` ORDER BY `PARTNO`";

关于javascript - 我需要明智地过滤数据ID吗?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/20512196/

10-11 16:20