jquery - jQuery为什么我无法显示对象？

$(function () {
    setTimeout(function() {
            var subcategory1 = $("body").find("#navCatLvl2 a");
            var OdjSubcategory1 = {};

            $(subcategory1).each(function(subcategory1,elem1) {

                    var num1 = subcategory1 + 1;
                    $(this).trigger('click');


                var ArrOdjSubcategory1 = {
                    "SubCategoryId1" : num1,
                    "Name" : $(this).attr('data-text')
                };

                OdjSubcategory1[num1] = ArrOdjSubcategory1;

            });
        console.log('OdjSubcategory1 = ' + OdjSubcategory1);
    }, 2000);
    console.log(OdjSubcategory1);
});

我们得到错误：


ReferenceError：在行OdjSubcategory1上未定义console.log(OdjSubcategory1);


如果console.log('OdjSubcategory1 = ' + OdjSubcategory1);显示OdjSubcategory1 = [object Object]为什么会出现错误？

最佳答案

您的console.log存在于setTimeout范围之外。 OdjSubcategory1不再存在（超出范围）。

请参阅以下代码中的注释：

$(function () {
    setTimeout(function() {
            var subcategory1 = $("body").find("#navCatLvl2 a");
            var OdjSubcategory1 = {};

            $(subcategory1).each(function(subcategory1,elem1) {

                    var num1 = subcategory1 + 1;
                    $(this).trigger('click');


                var ArrOdjSubcategory1 = {
                    "SubCategoryId1" : num1,
                    "Name" : $(this).attr('data-text')
                };

                OdjSubcategory1[num1] = ArrOdjSubcategory1;

            });
        console.log('OdjSubcategory1 = ' + OdjSubcategory1);
    }, 2000); // The scope of everything declared within setTimeout ends here
    console.log(OdjSubcategory1);
});

在console.log中移动setTimeout将解决您的问题。

关于jquery - jQuery为什么我无法显示对象？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/25322417/