这是我的代码,问题是当我发送电子邮件呼叫表单ID时,则不发送电子邮件;当我删除表单ID然后电子邮件发送时
HTMLCode和HTML之后是JS代码
这是我的代码,问题是当我发送电子邮件呼叫表单ID时,则不发送电子邮件;当我删除表单ID然后电子邮件发送时
<form id="main-contact-form" class="contact-form" name="contact-form" method="post" action="sendemail.php">
<div class="col-sm-5 col-sm-offset-1">
<div class="form-group">
<label>Name *</label>
<input type="text" name="name" class="form-control" required="required">
</div>
<div class="form-group">
<label>Email *</label>
<input type="email" name="email" class="form-control" required="required">
</div>
<div class="form-group">
<label>Phone</label>
<input type="number" class="form-control">
</div>
<div class="form-group">
<label>Company Name</label>
<input type="text" class="form-control">
</div>
</div>
<div class="col-sm-5">
<div class="form-group">
<label>Subject *</label>
<input type="text" name="subject" class="form-control" required="required">
</div>
<div class="form-group">
<label>Message *</label>
<textarea name="message" id="message" required="required" class="form-control" rows="8"></textarea>
</div>
<div class="form-group">
<button type="submit" name="submit" class="btn btn-primary btn-lg" required="required">Submit Message</button>
</div>
</div>
</form>
-
阿贾克斯代码
var form = $('#main-contact-form');
form.submit(function(event) {
event.preventDefault();
var form_status = $('<div class="form_status"></div>');
$.ajax({
url: $(this).attr('action'),
beforeSend: function() {
form.prepend(form_status.html('<p><i class="fa fa-spinner fa-spin"></i> Email is sending...</p>').fadeIn());
}
}).done(function(data) {
form_status.html('<p class="text-success">' + data.message + '</p>').delay(3000).fadeOut();
});
});
PHP代码
<?php
header('Content-type: application/json');
$status = array(
'type'=>'success',
'message'=>'Thank you for contact us. As early as possible we will contact you '
);
$name = @trim(stripslashes($_POST['name']));
$email = @trim(stripslashes($_POST['email']));
$subject = @trim(stripslashes($_POST['subject']));
$message = @trim(stripslashes($_POST['message']));
$email_from = $email;
$email_to = '[email protected]';//replace with your email
$body = 'Name: ' . $name . "\n\n" . 'Email: ' . $email . "\n\n" . 'Subject: ' . $subject . "\n\n" . 'Message: ' . $message;
$success = @mail($email_to, $subject, $body, 'From: <'.$email_from.'>');
echo json_encode($status);
die;
最佳答案
这就是您的ajax调用的外观
$('#main-contact-form').on('submit', function(event) {
event.preventDefault();
var form_status = $('<div class="form_status"></div>');
$.ajax({
url : $(this).attr('action'),
data : $(this).serialize(),
dataType : 'json',
type : 'POST',
beforeSend : function() {
form.prepend(form_status.html('<p><i class="fa fa-spinner fa-spin"></i> Email is sending...</p>').fadeIn());
}
}).done(function(data) {
form_status.html('<p class="text-success">' + data.message + '</p>').delay(3000).fadeOut();
});
});
关于javascript - 消息警报不起作用,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/40232629/