表格1
+----+--------+
| id | name |
+----+--------+
| 2 | robin |
| 3 | jyothi |
| 1 | angel |
+----+--------+
表2
+----+---------+--------+
| id | hobbies | ref_id |
+----+---------+--------+
| 1 | walking | 1 |
| 2 | chating | 1 |
| 3 | reading | 2 |
| 4 | walking | 2 |
+----+---------+--------+
我想要名字和他们的爱好,他们的爱好是“散步”或名字是“知更鸟”
+----+-----------------+
| name | hobbies |
+----+-----------------+
| 1 | walking,chating |
| 3 | reading,surfing |
+----+-----------------+
使用过的查询:
select name, group_concat(hobbies) as all_hobbies
from test1,test2
where test1.id = test2.ref_id
and test1.id in (select ref_id
from test2
where hobbies = 'walking')
group by name
我不想使用子查询或将整个结果保存为虚拟表,并通过where子句在all_hobbies上进行搜索。我想通过where子句或以某种方式完成group_concat列,因为它增加了我的SQL_JOIN_SZIE
我不能在这里使用它,因为它必须充当或条件,例如:
爱好是“散步”还是名字是“知更鸟”
最佳答案
我没有在这台机器上安装mysql,但是尝试执行此查询,我认为它应该可以工作。您可以将HAVING
子句视为WHERE
的GROUP BY
子句。
select name, group_concat(hobbies) as all_hobbies
from test1,test2
where test1.id = test2.ref_id and test1.name = 'robin'
group by name
having all_hobbies like '%walking%'
关于mysql - 如何将过滤条件放在group_concat列上?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/7204625/