我一直在研究一种基数桶排序算法,我先从两位数开始,然后逐步增加到更多位数。
我硬编码循环运行2次(因为我硬编码的数字中有2位数字),并且在第二个循环中有一个错误我无法确定。
介于清除数据向量和将值从存储桶推送到数据向量之间的某个地方,有些地方出错了……有什么想法吗?
错误只发生在一些数字输入…和其他人一样,我评论过它是有效的。
#include <math.h>
#include <iostream>
#include <vector>
using namespace std;
// test radix_sort
int main() {
cout << "==================================\n";
cout << "Radix bucket sort DEBUG ME\n";
cout << "==================================\n\n";
int m = 10;
int n = 1;
int arr[] = { 17, 45, 75, 90, 02, 24, 26, 06 }; //create data array
//int arr[] = { 170, 405, 750, 302, 002, 240, 206, 006 }; //create data array
vector<int> data (arr, arr + sizeof(arr) / sizeof(arr[0]) ); //create data vector
int elements = data.size();
//print data vector
cout << "Original: ";
for (int i = 0 ; i < elements ; i++){
cout << data[i] << " ";
}
cout << endl;
vector< vector<int> > vec(10, vector<int>(0));; //create buckets vector
for (int t = 0 ; t < 2 ; t++){ //hard coded to run 2 times since max 2 digits
for (int i = 0 ; i < elements ; i++) //radix sort into buckets
{
vec[(data[i]%m)/n].push_back(data[i]);
}
data.clear(); //clear from data vector
for (int i = 0 ; i < elements ; i++) //push buckets in order onto data
{
for (int j = 0 ; j < vec[i].size() ; j++)
{
data.push_back(vec[i][j]);
}
}
cout << "#" << t+1 << ": ";
for (int i = 0 ; i < elements ; i++){ //print data vector
cout << data[i] << " ";
}
cout << endl;
//multiply modulus by 10
m = m*10;
n= n*10;
for(int i = 0 ; i < 10 ; i++){ //clear all the shit from buckets
vec[i].clear();
}
}
return 0;
}
最佳答案
将值从vec
移回data
,您需要遍历所有10个bucket,而只需遍历其中的8个bucket:
for (int i = 0 ; i < elements ; i++) // elements == 8
{
for (int j = 0 ; j < vec[i].size() ; j++)
{
data.push_back(vec[i][j]);
}
}
这应该是:
for (int i = 0 ; i < vec.size(); i++) // vec.size() == 10
{
for (int j = 0 ; j < vec[i].size() ; j++)
{
data.push_back(vec[i][j]);
}
}
关于c++ - 基数桶搜索,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/29135668/