我认为我需要将其合并到某个位置,但是我找不到方法和位置。我要在StreamBuilder中使用吗?我带你到这里来等待您的帮助。
getCombinedMatches(uid) {
return Firestore.instance
.collection('matches')
.where('match', arrayContains: uid)
.snapshots()
.map((convert) {
return convert.documents.map((f) {
Observable<Matches> match = f.reference
.snapshots()
.map<Matches>((document) => Matches.fromMap(document.data));
Observable<User> user = Firestore.instance
.collection("users")
.document(uid)
.snapshots()
.map<User>((document) => User.fromMap(document.data));
Observable<Message> message = Firestore.instance
.collection('matches')
.document(f.documentID)
.collection("chat")
.orderBy('dater', descending: true)
.limit(1)
.snapshots()
.expand((snapShot) => snapShot.documents)
.map<Message>((document) => Message.fromMap(document.data));
return Observable.combineLatest3(match, user, message,
(matches, user, message) => CombinedStream(matches, user, message));
});
});
}
最佳答案
最后操作添加此代码
getCombinedMatches(uid) {
return Observable(Firestore.instance
.collection('matches')
.where('match', arrayContains: uid)
.snapshots())
.map((convert) {
return convert.documents.map((f) {
Stream<Matches> match = f.reference
.snapshots()
.map<Matches>((document) => Matches.fromMap(document.data));
Stream<User> user = Firestore.instance
.collection("users")
.document(uid)
.snapshots()
.map<User>((document) => User.fromMap(document.data));
Stream<Message> message = Firestore.instance
.collection('matches')
.document(f.documentID)
.collection("chat")
.orderBy('dater', descending: true)
.limit(1)
.snapshots()
.expand((snapShot) => snapShot.documents)
.map<Message>((document) => Message.fromMap(document.data));
return Observable.combineLatest3(match, user, message,
(matches, user, message) => CombinedStream(matches, user, message));
});
}).switchMap((observables) {
return observables.length > 0
? Observable.combineLatestList(observables)
: Observable.just([]);
});
}
关于Flutter将多个FireStore流与Rxdart结合,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/59109855/