我在显示子类中的某些字符串时遇到问题。我正在尝试使用一个函数,但是我不确定为什么我没有得到这些字符串的内容。
class Employee{
string FN, LN, JT;
double Income;
public:
char const *getters(){
return FN.data(), LN.data(), JT.data(); //=========>getting the content of strings
}
virtual char const *getAccess()=0;
Employee(char const *fn, char const *ln, char const *jt, double inc){
if(fn==0) throw Exception(1, "Sorry, First Name is Null");
if(ln==0) throw Exception(2, "Sorry, Last Name is Null");
if(jt==0) throw Exception(3, "Sorry Job Title is Null");
if(inc<=0) throw Exception(4, "Sorry, The Income is Null");
FN=fn;
LN=ln;
JT=jt;
Income=inc;
}
};
class Programmer: public Employee{
public:
Programmer(char const *fn, char const *ln, double inc):
Employee(fn,ln,"Programmer", inc)
{}
char const *getAccess(){
return "You have access to Meeting Room + Development Office";
}
};
//=========The Main============
int main(){
Employee *acc[3];
try{
acc[0]=new Programmer("Juan", "Villalobos", 60000);
acc[1]=new Director("Jorge", "Villabuena", 70000);
acc[2]=new ProdSupport("Pedro", "Villasmil", 80000);
for(int i=0; i<3; i++){
cout << acc[i]->getters() << endl; //=============>Displaying the strings
cout << acc[i]->getAccess() << endl;
}
} catch(Exception acc){
cout << "Err:" << acc.getErrCode() << " Mess:" << acc.getErrMess() << endl;
}
return 0;
}
因此,我猜测我的函数没有执行我想要的操作,即显示名字和姓氏。
我究竟做错了什么?
最佳答案
我不理解混合char*
和string
的意义。优先选择后者。
这确实可以编译
char const *getters(){
return FN.data(), LN.data(), JT.data();
}
但是你可能想要的是
char const *getters(){
return (FN + LN + JT).data();
}
我会这样重新编写您的程序:
class Employee{
string FN, LN, JT;
double Income;
public:
string getters(){
return FN + " " + LN + " " + JT;
}
virtual string getAccess()=0;
Employee(string const &fn, string const &ln, string const &jt, double inc) :
FN(fn), LN(ln), JT(jt), Income(inc)
{
}
};
class Programmer: public Employee{
public:
Programmer(string const &fn, string const &ln, double inc):
Employee(fn,ln,"Programmer", inc)
{}
string getAccess(){
return "You have access to Meeting Room + Development Office";
}
};
//=========The Main============
int main()
{
std::vector<Employee> acc;
acc.push_back(Programmer("Juan", "Villalobos", 60000));
acc.push_back(Director("Jorge", "Villabuena", 70000));
acc.push_back(ProdSupport("Pedro", "Villasmil", 80000));
for(size_t i=0; i<acc.size(); i++){
cout << acc[i].getters() << endl;
cout << acc[i].getAccess() << endl;
}
return 0;
}
关于c++ - C++处理我自己的异常类,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/18197780/