我的活跃记录是
$ql = $this->db->select('course_id')->from('tbl_course_choice')->where('course_id',$course_id)->get();
if( $ql->num_rows() > 0 ) {
$data = array(
'teacher_name_1' => 'mehdi'
);
$this->db->where('teacher_name_1', NULL);
$this->db->where('course_id', $course_id);
$this->db->update('tbl_course_choice', $data);
} else {
$a = array(
'course_id' => $course_id,
'course_code' => $course_code,
'course_title' => $course_title,
'course_type' => $course_type,
'credit_hours' => $credit_hours,
'contact_hours' => $contact_hours,
'section' => $section,
'teacher' => $teacher,
'pre_requisite' => $pre_requisite,
'year' => $year,
'semester' => $semester,
'offering_year' => $offering_year,
'offering_session' => $offering_session,
'teacher_name_1' => $teacher_name_1
);
$this->db->insert('tbl_course_choice', $a);
}
我需要检查字段是否为空,然后插入或更新,否则插入其他字段
if {
$this->db->where('teacher_name_1', NULL);
$this->db->where('course_id', $course_id);
$this->db->update('tbl_course_choice', $data);
}
elseif {
$this->db->where('teacher_name_1', IS NOT NULL);
$this->db->where('teacher_name_2', NULL);
$this->db->where('course_id', $course_id);
$this->db->update('tbl_course_choice', $data);
}
我该如何检查是否为null,然后插入或更新。任何人都可以帮助我吗?
最佳答案
使用自定义字符串
$this->db->where('teacher_name_1 IS NULL', NULL, FALSE);
关于php - 在Codeigniter中使用自定义where子句,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/22679423/