java - asSingleEntity()Java

我有下面的代码，它当前接受用户的“消息”，然后存储并显示它。目前，它仅显示一条消息，然后要求用户删除它，然后才能添加新消息。我想知道这是否是由asSingleEntity（）引起的，我该如何使用它进行更改以允许用户留下尽可能多的消息？

import java.security.SecureRandom;
import java.util.Iterator;
import java.util.LinkedList;
import java.util.List;

import com.google.appengine.api.datastore.DatastoreService;
import com.google.appengine.api.datastore.DatastoreServiceFactory;
import com.google.appengine.api.datastore.Entity;
import com.google.appengine.api.datastore.Key;
import com.google.appengine.api.datastore.Query;
import com.google.appengine.api.datastore.Query.FilterOperator;
import com.google.appengine.api.datastore.Query.SortDirection;
import com.google.appengine.api.datastore.Text;

// The application design is that authenticated users have zero or one messages.
//
// This class is not thread safe because it is possible to create 2 messages for
// a single user under the right conditions.  Also, the static initialization
// code is not thread safe either.  These problems can be solved using transactions.
//
// All application messages are placed under a single parent entity.
public class Message {

    private static final String parentKind = "messageParent";

    private static final String entityKind = "message";
    private static final String userIdPropertyName = "userId";
    private static final String nicknamePropertyName = "nickname";
    private static final String textPropertyName = "text";

    private static final String csrfTokenPropertyName = "csrfToken";

    private static Key parentKey = null;

    private static SecureRandom secureRandom = new SecureRandom();

    // Check if message parent exists; if not, then create it.
    static {
        Query query = new Query(parentKind);
        DatastoreService datastore = DatastoreServiceFactory.getDatastoreService();
        Entity parent = datastore.prepare(query).asSingleEntity();
        if (parent == null || parent != null) {
            parent = new Entity(parentKind);
            datastore.put(parent);
        }
        parentKey = parent.getKey();
    }

    private Entity entity = null;

    private Message(Entity entity) {
        this.entity = entity;
    }

    public Long getID() {
        return (Long) entity.getKey().getId();
    }

    public String getText() {
        return ((Text) entity.getProperty(textPropertyName)).getValue();
    }

    public String getNickname() {
        return (String) entity.getProperty(nicknamePropertyName);
    }

    private void setNickname(String nickname) {
        entity.setProperty(nicknamePropertyName, nickname);
    }

    private void setText(String text) {
        entity.setProperty(textPropertyName, new Text(text));
    }

    public String getCsrfToken() {
        return (String) entity.getProperty(csrfTokenPropertyName);
    }

    private void save() {
        DatastoreService datastore = DatastoreServiceFactory.getDatastoreService();
        datastore.put(entity);
    }

    public void delete() {
        DatastoreService datastore = DatastoreServiceFactory.getDatastoreService();
        datastore.delete(entity.getKey());
    }

    public static Message createOrUpdate(String userId, String nickname, String text) {
        Message message = getByUserId(userId);
        if (message != null) {
            message.setNickname(nickname);
            message.setText(text);
        } else {
            Entity entity = new Entity(entityKind, parentKey);
            entity.setProperty(userIdPropertyName, userId);
            entity.setProperty(nicknamePropertyName, nickname);
            entity.setProperty(textPropertyName, new Text(text));
            entity.setProperty(csrfTokenPropertyName, "" + secureRandom.nextLong());
            message = new Message(entity);
        }
        message.save();
        return message;
    }

    public static List<Message> getAll() {
        Query query = new Query(entityKind, parentKey).addSort(nicknamePropertyName, SortDirection.ASCENDING);
        DatastoreService datastore = DatastoreServiceFactory.getDatastoreService();
        Iterator<Entity> entityIter = datastore.prepare(query).asIterator();
        List<Message> messageList = new LinkedList<Message>();
        while (entityIter.hasNext()) {
            messageList.add(new Message(entityIter.next()));
        }
        return messageList;
    }

    public static Message getByUserId(String userId) {
        Query query = new Query(entityKind);
        query.addFilter(userIdPropertyName, FilterOperator.EQUAL, userId);
        DatastoreService datastore = DatastoreServiceFactory.getDatastoreService();
        Entity entity = datastore.prepare(query).asSingleEntity();
        if (entity == null) {
            return null;
        } else {
            return new Message(entity);
        }
    }
}

最佳答案

除了静态初始化程序中发生争用的可能性很小之外，使用单例父代的问题还在于，针对给定父代执行的每秒事务数有限制。如果您使用的是单例实例，那么您将遇到瓶颈。

使用一些杰出的实体作为实体组的父实体，您会获得更好的运气。比方说，一个实体，代表正在获取消息的用户。这具有消除静态初始化程序的好处。

关于java - asSingleEntity()Java，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/9458203/