MySQL表slalry:
aid year slalry
1 2000 1000
2 2001 2000
3 2002 3000
4 2003 4000
如何得到结果:
aid year slalry
1 2000 1000
2 2001 3000
3 2002 6000
4 2003 10000
最佳答案
sql代码:
SELECT
aid,year,
salary=(SELECT SUM(slalry) FROM slalry WHERE year<=A.year)
FROM slalry AS A;
关于mysql - 如何使用SQL查询逐年获取总薪水?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/1062982/