ruby - 如何对具有最高特定值的哈希排序？

我在数组nammedelem中有散列，我必须得到“type”键，它具有最高的“count”值。
我知道枚举数是一件很好的事情，但我不太了解他们。

elem = [{"type"=>"dododo", "count"=>0, "name"=>"dododo's", "tip"=>"dododo's Level"},
  {"type"=>"dadada", "count"=>1203, "name"=>"dadada's", "tip"=>"dadada's Degree"},
  {"type"=>"dedede", "count"=>717, "name"=>"dedede's", "tip"=>"dedede's Degree"},
  {"type"=>"dididi", "count"=>6, "name"=>"dididi's", "tip"=>"dididi or Professional Degree"}]

我在尝试：

elem.each do |i|
  i.each_with_index do |k,v|
    puts v["count"]
  end
end

但我知道我漏了一步。
我知道，这种“策略”是相当常见和重要的知道。

最佳答案

一种方法是使用Enumerable#max_by

elem = [
  {"type"=>"dododo", "count"=>0, "name"=>"dododo's", "tip"=>"dododo's Level"},
  {"type"=>"dadada", "count"=>1203, "name"=>"dadada's", "tip"=>"dadada's Degree"},
  {"type"=>"dedede", "count"=>717, "name"=>"dedede's", "tip"=>"dedede's Degree"},
  {"type"=>"dididi", "count"=>6, "name"=>"dididi's", "tip"=>"dididi or Professional Degree"}
]

max_elem = elem.max_by {|e| e['count']}
puts max_elem['type']
# returns dadada

关于ruby - 如何对具有最高特定值的哈希排序？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/24440415/