我不知道如何在标题中描述我的问题,但我希望它能做到。
这就是我的情况。
我使用休眠将我的实体映射到数据库表。
我有一个这样的实体:
@Entity
@Table(name = "EX.EXAMPLE")
public abstract class Entity
{
private CustomEntity customEntity;
public static final String CUSTOM_ENTITY = "customEntity";
@OneToOne(cascade = CascadeType.ALL, mappedBy = CustomEntity.ENTITY, fetch = FetchType.LAZY)
@Fetch(FetchMode.SELECT)
public CustomEntity getCustomEntity()
{
return this.customEntity;
}
}
还有我的CustomEntity
@Entity
@Table(name = "EX.EXAMPLE2")
public class CustomEntity
{
private Entity entity;
public static final String ENTITY = "entity";
@OneToOne
@JoinColumn(name = "ID_ENTITY", nullable = true)
public Entity getEntity()
{
return this.ntity;
}
}
所以这是我的问题:是否可以向Entity添加另一个CustomEntity关系?以及我如何映射它?
示例我的意思是:
@Entity
@Table(name = "EX.EXAMPLE")
public abstract class Entity
{
private CustomEntity customEntity;
public static final String CUSTOM_ENTITY = "customEntity";
private CustomEntity customEntity2;
public static final String CUSTOM_ENTITY2 = "customEntity2";
@OneToOne(cascade = CascadeType.ALL, mappedBy = CustomEntity.ENTITY, fetch = FetchType.LAZY)
@Fetch(FetchMode.SELECT)
public CustomEntity getCustomEntity()
{
return this.customEntity;
}
@OneToOne(cascade = CascadeType.ALL, mappedBy = CustomEntity.ENTITY, fetch = FetchType.LAZY)
@Fetch(FetchMode.SELECT)
public CustomEntity getCustomEntity2()
{
return this.customEntity2;
}
}
我仅通过将customEntity更改为Entity中的列表来进行管理。
问候
最佳答案
是的,那是完全正常的情况。您只需要两个字段具有不同的mappingBy`,每个关系一个
@OneToOne(cascade = CascadeType.ALL, mappedBy = CustomEntity.ENTITY1, fetch = FetchType.LAZY)
@Fetch(FetchMode.SELECT)
public CustomEntity getCustomEntity()
{
return this.customEntity;
}
@OneToOne(cascade = CascadeType.ALL, mappedBy = CustomEntity.ENTITY2, fetch = FetchType.LAZY)
@Fetch(FetchMode.SELECT)
@JoinColumn(name = "entity_2_id")
public CustomEntity getCustomEntity2()
{
return this.customEntity2;
}
在
CustomEntity
中有两个字段,每个字段对应一个 @OneToOne
@JoinColumn(name = "ID_ENTITY_1", nullable = true)
public Entity getEntity1()
{
return this.entity1;
}
@OneToOne
@JoinColumn(name = "ID_ENTITY_2", nullable = true)
public Entity getEntity2()
{
return this.entity2;
}
关于java - 在 hibernate 状态下是否可能有两次相同的“OneToOne”关系?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/29920720/