我正在尝试获取消息列表,一个表是所有未读消息的列表,另一个是所有已读消息的列表。我希望未读邮件在上次更新时排序,以便最新邮件始终位于顶部。
我写了以下查询,除了我得到一个错误,即订单依据未与联合啮合。我尝试将两个语句都用括号括起来,但是顺序错误。
SELECT threads.id AS thread,
updated_at
FROM threads
WHERE threads.id IN (SELECT thread_id
FROM posts
WHERE posts.id IN (SELECT post_id
FROM post_recipients
WHERE status = 1
AND
user_id = 'b1367cad-e1ea-31ba-beb9-2b53559eea17'))
ORDER BY updated_at DESC
UNION
SELECT thread_id AS thread,
updated_at
FROM thread_assignments
WHERE user_id = 'b1367cad-e1ea-31ba-beb9-2b53559eea17'
AND status = 0
AND thread_id NOT IN (SELECT threads.id AS thread
FROM threads
WHERE threads.id IN (SELECT thread_id
FROM posts
WHERE
posts.id IN (SELECT post_id
FROM post_recipients
WHERE status = 1
AND
user_id = 'b1367cad-e1ea-31ba-beb9-2b53559eea17'))
)
ORDER BY updated_at DESC;
需要明确的是,我不希望由updated_at排序的最终表,因为这可能会使已读消息比未读消息高。我要单独订购2张桌子,然后粘在一起。
最佳答案
根据Teson的建议,创建一个附加字段,以便您可以将两种类型分开
SELECT threads.id AS thread,
updated_at ,
0 as union_source
FROM threads
WHERE threads.id IN (SELECT thread_id
FROM posts
WHERE posts.id IN (SELECT post_id
FROM post_recipients
WHERE status = 1
AND
user_id = 'b1367cad-e1ea-31ba-beb9-2b53559eea17'))
UNION
SELECT thread_id AS thread,
updated_at,
1 as union_source
FROM thread_assignments
WHERE user_id = 'b1367cad-e1ea-31ba-beb9-2b53559eea17'
AND status = 0
AND thread_id NOT IN (SELECT threads.id AS thread
FROM threads
WHERE threads.id IN (SELECT thread_id
FROM posts
WHERE
posts.id IN (SELECT post_id
FROM post_recipients
WHERE status = 1
AND
user_id = 'b1367cad-e1ea-31ba-beb9-2b53559eea17'))
)
ORDER BY
union_source,
updated_at DESC;
关于mysql - 如何在工会中订购2张 table ?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/53619129/