mysql - 如何在zend db上的何处构建嵌套

大家好，我想在zend db（zf1.9）上构建此查询

SELECT `p`.*, `r`.`name` AS `retailer`, `placer`.`name` AS `placer_name`, `placer`.`contact_firstname` AS `placer_firstname`, `placer`.`contact_lastname` AS `placer_lastname`, `placer`.`role_id` AS `placer_role_id`, `editor`.`name` AS `editor_name`, `editor`.`contact_firstname` AS `editor_firstname`, `editor`.`contact_lastname` AS `editor_lastname`, `editor`.`role_id` AS `editor_role_id` FROM `pos` AS `p`
     LEFT JOIN `retailers` AS `r` ON r.id = p.retailer_id
     LEFT JOIN `members` AS `placer` ON placer.id = p.placer_id
     LEFT JOIN `members` AS `editor` ON editor.id = p.editor_id WHERE (p.designer_id=116) AND ((placer.name  LIKE   '%demo%') OR (placer.contact_firstname  LIKE   '%demo%') OR (placer.contact_lastname  LIKE   '%demo%') OR (r.name  LIKE   '%demo%')) AND (`r`.`name` LIKE  '%M%') ORDER BY `p`.`id` asc

我该怎么办？我的问题仅仅是

WHERE (p.designer_id=116) AND ((placer.name  LIKE   '%demo%') OR (placer.contact_firstname  LIKE   '%demo%') OR (placer.contact_lastname  LIKE   '%demo%') OR (r.name  LIKE   '%demo%')) AND (`r`.`name` LIKE  '%M%')

最佳答案

只需将嵌套的where子句拆分为多个and语句（带有嵌套的or）：

第一：

(p.designer_id=116)

第二：

((placer.name LIKE '%demo%') OR (placer.contact_firstname LIKE '%demo%') OR (placer.contact_lastname LIKE '%demo%') OR (r.name  LIKE '%demo%'))

第三：

(`r`.`name` LIKE '%M%')

在ZEND中，每个AND都是一个单独的where子句，可能看起来像这样（未经测试！只是为了更好地理解！）：

->where("p.designer_id=116");
->where("(placer.name  LIKE ?)
        OR (placer.contact_firstname LIKE ?)
        OR (placer.contact_lastname LIKE ?)
        OR (r.name LIKE ?)", '%demo%', '%demo%', '%demo%', '%demo%');
->where("r.name LIKE ?", '%M%');

（注意：我添加了手动换行符以提高可读性）

关于mysql - 如何在zend db上的何处构建嵌套，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/18881230/