以下查询按预期工作。
但是如何在列中显示的行中获得结果？
select curdate() AS one,
date_sub(curdate(), interval 15 day) AS two
, date_sub(curdate(), interval 30 day) AS three
, date_sub(curdate(), interval 45 day) AS four
, date_sub(curdate(), interval 60 day) AS five
, date_sub(curdate(), interval 75 day) AS six
, date_sub(curdate(), interval 90 day) AS seven
;
| one | two | three | four | five | six | seven |
+------------+------------+------------+------------+------------+------------+------------+
| 2010-09-27 | 2010-09-12 | 2010-08-28 | 2010-08-13 | 2010-07-29 | 2010-07-14 | 2010-06-29 |
连续预期结果:
one 2010-09-27
two 2010-09-12
three 2010-08-28
four 2010-08-13
five 2010-07-29
six 2010-07-14
seven 2010-06-29
最佳答案
您可以为此使用 UNION ALL
select 'one' as label, curdate() as val
UNION ALL
select 'two' as label, date_sub(curdate(), interval 15 day) as val
UNION ALL
select 'three' as label, date_sub(curdate(), interval 30 day) as val
UNION ALL
select 'four' as label, date_sub(curdate(), interval 45 day) as val
UNION ALL
select 'five' as label, date_sub(curdate(), interval 60 day) as val
UNION ALL
select 'six' as label, date_sub(curdate(), interval 75 day) as val
UNION ALL
select 'seven' as label, date_sub(curdate(), interval 90 day) as val
关于sql - 将列转置为行，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/3802219/