c# - 如何在选择查询中添加功能

select new FeedResource
{
   Title = (string)details.Element("title"),
   Host = (string)details.Element("link"),
   Description = (string)details.Element("description"),
   PublishedOn = (DateTime?)details.Element("pubDate"),
   Generator = (string)details.Element("generator"),
  Language = (string)details.Element("language")
}

在上面的代码中，我想将类型转换值传递给另一个函数，
例

Description = getValidDescription((string) details.Element("description"))

但我无法实现，有什么投入吗？

注意：必须使用类型转换才能处理空值（如果“描述”不存在任何值，则它（XElement）可以完美处理空值）。

最佳答案

对我来说很好错误消息是什么？例：

// doesn't have to be static - just simpler for my test
static string getValidDescription(string description)
{
    // handle nulls safely (could return a default here)
    if (description == null) return null;
    // for example only...
    return CultureInfo.CurrentCulture.TextInfo
        .ToTitleCase(description);
}

var qry =
    from details in doc.Root.Elements("detail")
    select new FeedResource
    {
        Title = (string)details.Element("title"),
        Host = (string)details.Element("link"),
        Description = getValidDescription((string) details.Element("description")),
        PublishedOn = (DateTime?)details.Element("pubDate"),
        Generator = (string)details.Element("generator"),
        Language = (string)details.Element("language")
    };

关于c# - 如何在选择查询中添加功能，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/1905025/