mysql - 嵌套查询返回值

我有一张这样的桌子

 id |  SKU  |  quantity_purchased | discount_price
---------------------------------------------------
1   | abc   |   1                 |     10.0
2   | abc   |   90                |     00
2   | abc   |   9                 |     00
3   | xyz   |   1                 |     50.0
3   | xyz   |   2                 |     50.0
4   | xyz   |   100               |     00
4   | xyz   |   100               |     00
-----------------------------------------------

我的问题是

select
(select sum(quantity_purchased)  from order_details where discount_price > 0.00) as qty_discount,
(select sum(quantity_purchased)  from order_details where discount_price = 0.00)as qty_original,
sku
from order_details
GROUP BY sku

我要求的结果是

  SKU   |  quantity_original | quantity_discount
---------------------------------------------------
 abc    |   1                 |     99
 xyz    |   3                 |     200
-----------------------------------------------

也就是说，经过计算，我需要两列相同的order_details，
我无法建立逻辑，我尝试在嵌套查询中使用sku，但它不起作用。。。
任何帮助都非常感谢。。
谢谢
更新：
试着通过这个但还是失败了，

select
(select sum(quantity_purchased)  from order_details where discount_price > 0.00 ) as qty_discount,
(select sum(quantity_purchased)  from order_details where discount_price = 0.00 )as qty_original,
sku
from order_details
where sku = (select distinct sku from order_details)
GROUP BY sku

最佳答案

您可以使用conditional aggregation来执行以下操作：

select sku,
       sum(case when discount_price != 0 then quantity_purchased
                else 0
           end) quantity_original,
       sum(case when discount_price = 0 then quantity_purchased
                else 0
           end) quantity_discount
from order_details
group by sku

SQL Fiddle Demo

Results:

| SKU | quantity_original | quantity_discount |
|-----|-------------------|-------------------|
| abc |                 1 |                99 |
| xyz |                 3 |               200 |

关于mysql - 嵌套查询返回值，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/35818659/