我正在使用pthreads库来尝试和实现带有监视器的读取器/写入器应用程序。
我主要通过以下方式调用线程函数
pthread_t *tid;
tid = (pthread_t*)malloc(sizeof(pthread_t)*(r + w));
int addr = 0;
//Create r # readers
for (int a = 0; a < r; a++)
{
pthread_create(&tid[addr], NULL, Reader, (void*)&a);
addr++;
}
然后他们通过以下3个函数调用来完成其功能
void *Reader(void *pid)
{
static int *id = (int*)pid;
for (int i = 0; i < 10; i++)
{
beginRead(id);
endRead();
#ifdef __unix
usleep(R);
#endif
#ifdef _WIN32
Sleep(R);
#endif
}
return 0;
}
void beginRead(int *id)
{
//If writelock or writer_queued then wait(canRead)
pthread_mutex_lock(&writelock);
while (writer_queued)
{
reader_queued = true;
pthread_cond_wait(&canRead, &writelock);
reader_queued = false;
}
readers++;
pthread_mutex_unlock(&writelock);
pthread_mutex_lock(&output);
time_t t = time(0);
struct tm * now = localtime(&t);
fprintf(outputfile, "DB value read =:%d:%d by reader number: %d\n", now- >tm_sec, (now->tm_sec) / 1000, (int)*id);
printf("DB value read =:%d:%d by reader number: %d\n", now->tm_sec, (now->tm_sec)/1000, (int)*id);
pthread_mutex_unlock(&output);
pthread_cond_broadcast(&canRead);
}
void endRead()
{
--readers; // just finished a reader
if (readers == 0)
{
pthread_cond_signal(&canWrite);
}
}
这应该使每个线程进入代码的关键部分10次(因此,如果创建了2个线程,它将访问关键部分20次)我让线程以正确的次数访问代码的关键部分。次,我只是无法获取它以打印正确的线程ID#
因此,如果我用r = 2和R = 200调用此函数,我的输出将是:
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
什么时候应该是类似的东西
DB value read =:30:0 by reader number:1
DB value read =:30:0 by reader number:1
DB value read =:30:0 by reader number:1
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number:1
DB value read =:30:0 by reader number:1
DB value read =:30:0 by reader number:1
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number:1
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number:1
DB value read =:30:0 by reader number:1
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number:1
DB value read =:30:0 by reader number:1
DB value read =:30:0 by reader number:1
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
DB value read =:30:0 by reader number: 2
取决于每个线程访问关键部分的时间
最佳答案
该代码将相同的地址(a
的地址)传递给每个线程。
您要向每个线程传递一个单独的地址。
您可以这样做,例如:
struct thread_info
{
pthread_t tid;
int id;
}
...
struct thread_info * pti = malloc((r + w) * sizeof *pit);
size_t addr = 0;
//Create r # readers
for (int a = 0; a < r; a++)
{
pti[addr]->id = a;
pthread_create(&pti[addr]->tid, NULL, Reader, &pti[addr]->id);
addr++;
}
也是这条线
--readers; // just finished a reader
同时访问不受保护的
readers
。关于c - 带显示器的读写器,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/47233418/