c++ - 使用C++进行切换会跳过所有情况，并且会连续t

This question already has answers here:

Why the switch statement cannot be applied on strings?
                                
                                    （19个回答）
                                
                        
                        
                            Single quotes vs. double quotes in C or C++
                                
                                    （12个答案）
                                
                        
                                3年前关闭。
            
                    
我是这个网站的新手，但是现在大约一个学期就开始学习编程课程。我只是有一个问题，为什么我的程序会跳过所有情况，变为默认状态，并立即关闭而不停止或执行任何操作。这可能只是一件小事，但我一直坐在这里，看不到它。这是代码。谢谢您的帮助：

//Name Game
#include <iostream>
#include <fstream>
#include <stdlib.h>
#include <math.h>
#include <iomanip>
using namespace std;
int main(void)
{
    char name, zzz;
    cout << "Hello, and welcome to the start of a fantastic new adventure. \nI'm your guide for the day: Sebastian.  \nMay I ask what your name is?\n";
    cin >> name;
    switch (name)
    {
    case 'alex':
    case 'Alex':
        cout << "What an absolutely beautiful name. It sends chills down my spine just thinking about it. \nYou're one lucky girl.";
        cout << "\nI've heard from my friend that you are as beautiful as your name suggests.";
        break;
    case 'Ryan':
    case 'ryan':
        cout << "Please stop using this project.  What are you even doing here?";
        break;
    default:
        cout << "That's a nice name.  You should keep it for as long as you can.";
        cin >> zzz;
        return (0);
    }
    return 0;
}

最佳答案

char只是一个字符，而不是全名。

当您阅读char时，它将是a或A或,，但不会是Alex。

您必须为此任务使用字符串，这些字符串以"double"引号而不是'single'引号书写。

关于c++ - 使用C++进行切换会跳过所有情况，并且会连续t ，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/36777252/