swift - Swift 3预期参数错误

我正在创建一些功能，以便使一个游戏类似于Flappy Bird。我是一个完全的初学者，并试图了解一切，因为我走之前，继续。我已经能够让我的障碍移动，但当我试图把它变成一个函数，让我更灵活，后来有多个障碍，我会收到一个错误。
'无法将类型'）'转换为所需的参数类型'SKAction'
类游戏场景：SKScene，skphysiccontactdelegate{

var Player = SKSpriteNode()
var Ground = SKSpriteNode()
var Roof = SKSpriteNode()
var Background = SKSpriteNode()
let Obstacle1 = SKSpriteNode(imageNamed: "Fire Barrel 1")

override func didMove(to view: SKView) {

    // Create Background Color
    backgroundColor = bgColor

    // Set World Gravity
    self.physicsWorld.gravity = CGVector(dx: 0.0, dy: -4.0)

    // Create Player
    Player = SKSpriteNode(imageNamed: "Player")
    Player.setScale(0.5)
    Player.position = CGPoint(x: -self.frame.width / 2 + 100, y: -Player.frame.height / 2)

    self.addChild(Player)

    // Create Ground
    Ground = SKSpriteNode(imageNamed: "BGTileBtm")
    Ground.anchorPoint = CGPoint(x: 0,y: 0.5)
    Ground.position = CGPoint(x: -self.frame.width / 2, y: -self.frame.height / 2)

    self.addChild(Ground)

    // Create Roof
    Roof = SKSpriteNode(imageNamed: "BGTileTop")
    Roof.anchorPoint = CGPoint(x: 1,y: 1)
    Roof.position = CGPoint(x: -self.frame.width / 2, y: self.frame.height / 2 - Roof.frame.height)
    Roof.zRotation = CGFloat(M_PI)

    self.addChild(Roof)

    // Set Physics Rules
    Player.physicsBody = SKPhysicsBody(texture: SKTexture(imageNamed: "Player"), size: Player.size)
    Player.physicsBody!.affectedByGravity = true
    Player.physicsBody!.allowsRotation = false

    Ground.physicsBody = SKPhysicsBody(texture: SKTexture(imageNamed: "Ground"), size: Ground.size)
    Ground.physicsBody!.affectedByGravity = false
    Ground.physicsBody!.isDynamic = false

    // Obstacle
    func addObstacle1(){

        Obstacle1.position = CGPoint(x: self.frame.width / 2, y: -self.frame.height / 2 + Obstacle1.frame.height)
        Obstacle1.zPosition = 1
        addChild(Obstacle1)
    }

    func moveObstacle1(){

        let distance = CGVector(dx: -self.frame.width, dy: 0)
        let moveDistance = SKAction.move(by: distance, duration: 5)
        run(moveDistance)

    }

    addObstacle1()
    Obstacle1.run(moveObstacle1())


}

最佳答案

将moveObstacle1的声明更改为：

func moveObstacle1() -> SKAction{

    let distance = CGVector(dx: -self.frame.width, dy: 0)
    let moveDistance = SKAction.move(by: distance, duration: 5)
    return moveDistance

}

编辑：
关于你的评论，
run是一种方法。当你调用它时，它运行你传入的SKAction。就这样！你要做的是run(moveObstacle1())。那到底是什么意思？如何将方法调用作为参数传递？在运行时，moveObstacle1()的返回值传递给run。换句话说，要编译run(moveObstacle1())，moveObstacle1()必须使用return语句返回一个值。这个值必须是SKAction类型，因为这是您传递给run的内容。
return用于从moveObstacle1()返回值，以便您可以调用run(moveObstacle1())。
run只是一种常规的老方法。

关于swift - Swift 3预期参数错误，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/40074479/