javascript - 应用上下文TypeError时出错:无法读取null的属性'getReferences'

应用程序抛出空错误，尝试了一些尝试，但是没有运气，似乎很简单，但却无法弄清我的一生，不确定我缺少什么。希望有人能看到问题。

**登录**

RouteToMarketSearch.RouteToMarketSearchSnippet.referenceSetDisplay2: Error while applying context Error: RouteToMarketSearch.RouteToMarketSearchSnippet.referenceSetDisplay2: Error while applying context TypeError: Cannot read property 'getReferences' of null Error: RouteToMarketSearch.RouteToMarketSearchSnippet.referenceSetDisplay2: Error while applying context Error: RouteToMarketSearch.RouteToMarketSearchSnippet.referenceSetDisplay2: Error while applying context TypeError: Cannot read property 'getReferences' of null

声明变量

_handles: null,
_contextObj: null,
_reference : null,
_entity : null,
_intersectReference : null,
_intersectEntity : null,

**代码**

_updateRendering: function (callback) {
    logger.debug(this.id + "._updateRendering");
    var self = this;
    if(this.rsdListContainer){
        data.get({
            guids: this._contextObj.getReferences(this._reference),
            callback: function(objs){
                if(self.rsdListContainer){
                    var intersectGuids = [];
                    if(self._intersectReference){
                        intersectGuids = self._contextObj.getReferences(self._intersectReference);
                    }

                    var dataArray = objs.map(function(o){
                        var data = {};
                        data.guid = o.getGuid();
                        data.caption = o.get(self.displayAttribute);
                        if( intersectGuids && intersectGuids.indexOf(o.getGuid()) > -1){
                            data.elementClass = self.intersetResultClass;
                        }
                        if(self.sortAttribute){
                            data.sortIndex = parseInt(o.get(self.sortAttribute));
                        }

                        return data;
                    });

                    if(self.sortAttribute){
                        dataArray.sort(function(a,b){
                                return a.sortIndex - b.sortIndex;
                        });
                    }

                    dojoConstruct.empty(self.rsdListContainer);

最佳答案

如果使用空值声明_contextObj，则在尝试执行this._contextObj.getReferences时会抛出该错误。没有内部实现的空值，您需要声明它或限制其访问

关于javascript - 应用上下文TypeError时出错:无法读取null的属性'getReferences'，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/60210752/