context.Projects
.Include(x => x.Members) //List<Member> public class Member
.Include(x => x.Members.Select(z => z.City)) //public class City
.ToList();
从中选择项目
包括项目列表。成员
包括每个项目。成员。城市
需要添加一些数据才能得出结果
context.Projects
.Include(x => x.Members)
.Include(x => x.Members.Select(z => z.City))
.Select(x => new {
Project = x,
Amount = 22
})
.ToList();
项目属性已填充,但成员为空
问题1-如何包含 Project。将和新增为{Project = x} 成员
我接下来
context.Projects
.Include(x => x.Members) //List<Member>
.Include(x => x.Members.Select(z => z.City)) //City is navigation property
.Select(x => new {
Project = x,
Members = x.Members,
Amount = 22
})
.ToList();
已填充项目属性,并已填充成员但已填充Members [0]。城市为空
问题2-如何填充成员[0]。城市
P.S.
Entity Framework 6
public class Project
{
public Guid Id { get; set; }
public string Name { get; set; }
public List<ProjectMember> Members { get; set; }
}
public class ProjectMember
{
public Guid ProjectId { get; set; }
public Project Project { get; set; }
public Guid CityId { get; set; }
public City City { get; set; }
}
压力
这项工作-但代码开销
context.Projects
.Include(x => x.Members) //List<Member>
.Include(x => x.Members.Select(z => z.City)) //City is navigation property
.Select(x => new {
Project = x,
Members = x.Members.Select(z => new {
Item = z,
City= z.City
}).ToList(),
Amount = 22
})
.ToList();
最佳答案
您在包含之后执行的任何操作(过滤除外)都将导致包含被丢弃。通过在包含之后调用AsEnumerable
,您将确保查询随后被执行,其余操作将在内存中完成:
context.Projects
.Include(x => x.Members)
.Include(x => x.Members.Select(z => z.City))
.AsEnumerable()
.Select(x => new { Project = x, Amount = 22 })
.ToList();
关于c# - Linq EF Include()与Select()新类型丢失,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/36071987/