我正在使用flask，在此给出示例，我想做什么。我从烧瓶门户网站复制了代码。
from flask import Flask
app = Flask(__name__)
@app.route('/')
def hello_world():
return 'Hello, World!'
运行应用
(py35) root@localhost:tmp root$ flask run
* Serving Flask app "hello"
* Running on http://127.0.0.1:5000/ (Press CTRL+C to quit)
发送请求
root@localhost:~ root$ curl http://localhost:5000/
Hello, World!
我修改了函数并进行了更改以引发错误。
@app.route('/')
def hello_world():
print(xyz)
return 'Hello, World!'
当我尝试发送请求时，失败
[2017-11-06 10:22:13,625] ERROR in app: Exception on / [GET]
Traceback (most recent call last):
File "/py35/lib/python3.5/site-packages/flask/app.py", line 1982, in wsgi_app
response = self.full_dispatch_request()
File "/py35/lib/python3.5/site-packages/flask/app.py", line 1614, in full_dispatch_request
rv = self.handle_user_exception(e)
File "/py35/lib/python3.5/site-packages/flask/app.py", line 1517, in handle_user_exception
reraise(exc_type, exc_value, tb)
File "/Users/nile2691/sbdev/StorageCenterUI/.tox/py35/lib/python3.5/site-packages/flask/_compat.py", line 33, in reraise
raise value
File "/py35/lib/python3.5/site-packages/flask/app.py", line 1612, in full_dispatch_request
rv = self.dispatch_request()
File "py35/lib/python3.5/site-packages/flask/app.py", line 1598, in dispatch_request
return self.view_functions[rule.endpoint](**req.view_args)
File "/private/tmp/hello.py", line 6, in hello_world
print(xyz)
NameError: name 'xyz' is not defined
我可以在代码中添加
try...except，但是在实际代码中，很多地方都可以添加，我不想在任何地方都处理此一般异常。有什么办法吗
try:
process_flask_request()
except Exception as ex:
# Log detail exception
logger.exception(ex)
return "Custome error message for all general exception"
进行此更改后，不会出现如下所示的一般错误
curl http://localhost:5000/
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 3.2 Final//EN">
<title>500 Internal Server Error</title>
<h1>Internal Server Error</h1>
<p>The server encountered an internal error and was unable to complete your request. Either the server is overloaded or there is an error in the application.</p>
我想返回正确的输出，并带有自定义错误消息。
最佳答案
您可以包含这样的错误处理程序，例如在您的示例中更好地显示内部服务器错误：
import traceback
(...some code...)
@app.errorhandler(500)
def internal_error(e):
"""
handle internal errors nicely
"""
tb = traceback.format_exc()
return render_template('error.html',
error=e.message,
traceback=tb), 500
然后，您可以在模板中输出简短的错误消息，以及（如果您具有用户管理，则取决于用户权限）详细的堆栈跟踪。
正如您对问题的评论中提到的那样，您应该阅读文档以获取完整信息。
关于python - 如何在单个位置处理 flask 中的一般异常？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/47141503/