swift - swift 冲突的UIPickerView

我一直在试图弄清楚为什么picker视图向我的函数发送冲突的结果。当我更改一个选择器视图时，它将覆盖由上一个选定选择器视图设置的值。pickerviews之间的共同点是它们是用相同的数组填充的。下面是控制pickerview和窗体屏幕截图的代码。当首先选择顶部贷方，最后选择底部贷方时，公式使用底部贷方进行计算。但是，如果我通过先选择最底层的贷方，然后再选择最上层的贷方来颠倒顺序，那么它将使用最上层的贷方来计算。选择包含60的值时也会发生同样的错误。选定的最后一个值设置传递给公式的值。每个选定值都需要保留其自己的选定值

 func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {

    if pickerView == currentLenderPicker
        {
            return newLender[row]
    }
    else if pickerView == newLenderPicker
    {
        return newLender[row]
    }
    else if pickerView == currentPaymentFrequencyPicker
    {
        return paymentFrequency[row]
    }
    else if pickerView == newPaymentFrequencyPicker
    {
        return paymentFrequency[row]
    }
    else if pickerView == mortgageTermPicker
    {
        return mortgageTerm[row]
    }
    else if pickerView == newMortgageTermPicker
    {
        return mortgageTerm[row]
    }
    return ""

}


func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {

    if pickerView == currentLenderPicker
        {
            return lenders.count
    }
    else if pickerView == newLenderPicker
    {
        return newLender.count
    }
    else if pickerView == currentPaymentFrequencyPicker
    {
        return paymentFrequency.count
    }
    else if pickerView == newPaymentFrequencyPicker
    {
        return paymentFrequency.count
    }
    else if pickerView == mortgageTermPicker
    {
        return mortgageTerm.count
    }
    else if pickerView == newMortgageTermPicker
    {
        return mortgageTerm.count
    }
    return 1
}

func numberOfComponents(in pickerView: UIPickerView) -> Int {


    return 1
}

    func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {

        if pickerView == currentLenderPicker
        {
            orginalLender.text = lenders[row]

        }
        else if pickerView == newLenderPicker
        {
            newMortgageLender.text = newLender[row]

        }
        else if pickerView == currentPaymentFrequencyPicker
        {
            currentPaymentFrequency.text = paymentFrequency[row]
        }
        else if pickerView == newPaymentFrequencyPicker
        {
            newPaymentFrequency.text = paymentFrequency[row]
        }

        else if pickerView == mortgageTermPicker
        {
            currentMortgageTerm.text = mortgageTerm[row]
        }
        else if pickerView == newMortgageTermPicker
        {
            newMortgageTerm.text = mortgageTerm[row]
        }

        if let selectedLender = currentLender.filter({ $0.fiName == lenders[row] }).first {
            Global.selectedRate = selectedLender
        }

        self.view.endEditing(false)
}

我用标签做了更改，但我仍然有同样的问题。更新了下面的代码。

    // Load FI Information

   func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {

    if pickerView.tag == 1
        {
            return newLender[row]
    }
    else if pickerView.tag == 11
    {
        return newLender[row]
    }
    else if pickerView.tag == 10
    {
        return paymentFrequency[row]
    }
    else if pickerView.tag == 15
    {
        return paymentFrequency[row]
    }
    else if pickerView.tag == 6
    {
        return mortgageTerm[row]
    }
    else if pickerView.tag == 17
    {
        return mortgageTerm[row]
    }
    return ""

}


func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {

    if pickerView.tag == 1
        {
            return lenders.count
    }
    else if pickerView.tag == 11
    {
        return newLender.count
    }
    else if pickerView.tag == 10
    {
        return paymentFrequency.count
    }
    else if pickerView.tag == 15
    {
        return paymentFrequency.count
    }
    else if pickerView.tag == 6
    {
        return mortgageTerm.count
    }
    else if pickerView.tag == 17
    {
        return mortgageTerm.count
    }
    return 1
}

func numberOfComponents(in pickerView: UIPickerView) -> Int {


    return 1
}

    func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {

        if pickerView.tag == 1
        {
            orginalLender.text = lenders[row]

        }
        else if pickerView.tag == 11
        {
            newMortgageLender.text = newLender[row]

        }
        else if pickerView.tag == 10
        {
            currentPaymentFrequency.text = paymentFrequency[row]
        }
        else if pickerView.tag == 15
        {
            newPaymentFrequency.text = paymentFrequency[row]
        }

        else if pickerView.tag == 6
        {
            currentMortgageTerm.text = mortgageTerm[row]
        }
        else if pickerView.tag == 17
        {
            newMortgageTerm.text = mortgageTerm[row]
        }

        if let selectedLender = currentLender.filter({ $0.fiName == lenders[row] }).first {
            Global.selectedRate = selectedLender
        }

        self.view.endEditing(false)
}

最佳答案

您应该使用标记来指示特定的pickerView。检查这个答案，它会把事情弄清楚的
Implement PickerView With Tag
希望有帮助。

关于swift - swift 冲突的UIPickerView，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/45426793/