c - 从不兼容的指针类型传递'listFind'的arg2

我的函数遇到了一些问题，不知道如何解决此问题，这是我的代码：

ListResult result=listFind(currentLines, compareBasicLines, &linePrototype);  <-here problem

compareBasicLines指向函数的指针

int compareBasicLines(ptrLine line1, ptrLine line2){
    COMPARE_NUMBER_STRINGS(line1, line2);
}

在另一个文件中定义的COMPARE_NUMBER_STRINGS(line1, line2);

#define COMPARE_NUMBER_STRINGS(var1, var2)                              \
                    if(var1 == NULL || var2 == NULL){                   \
                        return 0;                                       \
                    }                                                   \
                    return strcmp(var1->strNumber, var2->strNumber);

在此先感谢大家

这就是我所拥有的，我的作业是关于ADT的，所以我不知道列表里面有什么内容

/**
 * Searches the list for an element fitting the criteria starting from the
 * current element.
 * Note that you need to call listGetFirst if you wish to search from the start
 * of the list. The search starts from the current element.
 * @param list
 *  The list to search in
 * @param compare
 *  Comparison function to decide if an element in the last is equal to the
 *  target elemnt. This function should return 0 for equal elements
 * @param target
 *  A target element to compare with each element in the list.
 * @return
 *  LIST_NULL_ARGUMENT if list or compare are NULL
 *  LIST_INVALID_CURRENT if the current pointer of the list is in invalid state
 *  LIST_NO_SUCH_ELEMENT if no element was found from the current element until
 *  the end of the list
 *  LIST_SUCCESS an element was found and the current pointer of the list is now
 *  set to this element
 *
 */

ListResult listFind(List list, CompareListElements compare, ListElement target);

还有一个定义

typedef int (*CompareListElements)(ListElement, ListElement);

typedef void* ListElement;

最佳答案

listFind()的第二个参数的类型为int (*)(ptrLine, ptrLine)。这显然与listFind()声明中第二个参数的类型不同。

如果没有看到listFind()的定义，很难说出应如何解决。

关于c - 从不兼容的指针类型传递'listFind'的arg2，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/2816969/