我试图用特定格式打印一个输出，其中输出放在一个封闭的框中。
我用“”和“-”来创建它。我在“”之间打印的输出是具有不同字符数的变量。
这弄乱了我的格式。
我试过下面的代码
nodename=$(hostname)
cpu=$(cat /proc/cpuinfo | awk '/^processor/{print $3}' | wc -l)
echo " ------------------------------------------------------------------"
echo "| |"
echo "| This is Bash Scripting |"
echo "| |"
echo "| 1 - This Machine Name is $nodename |"
echo "| 2 - This Machine has $cpu CPU's |"
echo "| |"
echo " -------------------------------------------------------------------"
实际结果
" ------------------------------------------------------------------"
"| |"
"| This is Bash Scripting |"
"| |"
"| 1 - This Machine Name is test |"
"| 2 - This Machine has 8 CPU's |"
"| |"
" -------------------------------------------------------------------"
预期结果
" ------------------------------------------------------------------"
"| |"
"| This is Bash Scripting |"
"| |"
"| 1 - This Machine Name is test |"
"| 2 - This Machine has 8 CPU's |"
"| |"
" -------------------------------------------------------------------"
最佳答案
使用printf而不是echo：
printf "| 1 - This Machine Name is %-39s|\n" "$nodename"
您可以使用
%-39s指定右空格填充。关于linux - 可变长度未知的水平和垂直线间距，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/57627132/