我在C ++中有一个类模板,而另一个类继承了它。正如您将看到的,后者不是类模板。当我尝试通过调用基类(模板一)的构造函数来定义派生类的构造函数时,就会出现问题。我已将错误发布到代码下方。
为了简单起见,我仅添加了声明。如果您认为代码可以帮助您了解问题的根源,我们将很乐意将其发布。
状态2d.h
#ifndef STATE2D_H
#define STATE2D_H
template <typename T>
class State2D
{
public:
State2D(unsigned int _rows, unsigned int _columns);
State2D(unsigned int _rows, unsigned int _columns, const T& val);
State2D(const State2D<T> &st);
~State2D();
T& operator()(unsigned int i, unsigned int j);
const T& operator()(unsigned int i, unsigned int j) const;
unsigned int GetRowCount() const;
unsigned int GetColumnCount() const;
unsigned int GetAvailablePositionsCount() const;
protected:
T** matrix;
unsigned int rows;
unsigned int columns;
unsigned int availablePositions;
};
#endif // STATE2D_H
TicTacToeState.h
#ifndef TICTACTOESTATE_H
#define TICTACTOESTATE_H
#include "state2d.h"
class TicTacToeState : public State2D<char>
{
public:
TicTacToeState();
};
#endif // TICTACTOESTATE_H
TicTacToeState.cpp
#include "tictactoestate.h"
TicTacToeState::TicTacToeState() : State2D(3,3,' ') // ERROR here; see below
{
}
错误:类“ TicTacToeState”没有名为“ State2D”的任何字段
错误:没有匹配的函数来调用“ State2D :: State2D()”
候选对象是:State2D :: State2D(const State2D&)[with T = char]
State2D :: State2D(unsigned int,unsigned int,const T&)[with T = char]
State2D :: State2D(unsigned int,unsigned int)[with T = char]
有任何想法吗?
最佳答案
: State2D<char>(3,3,' ')
也许?
关于c++ - 模板继承,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/12460960/