有没有办法让 sliderInput
等待几秒钟,然后再更改其对应的input$
变量?我有一个控制图形的栏,该图形需要在值更改时重新呈现。我知道使用提交按钮的解决方法,我希望避免这种情况。
最佳答案
您可以使用invalidateLater
。可以通过天真但简洁的方式来完成:
library(shiny)
shinyApp(
server = function(input, output, session) {
values <- reactiveValues(mean=0)
observe({
invalidateLater(3000, session)
isolate(values$mean <- input$mean)
})
output$plot <- renderPlot({
x <- rnorm(n=1000, mean=values$mean, sd=1)
plot(density(x))
})
},
ui = fluidPage(
sliderInput("mean", "Mean:", min = -5, max = 5, value = 0, step= 0.1),
plotOutput("plot")
)
)
这种方法的问题在于,当更改滑块输入并触发
invalidate
事件时,您仍然可以触发执行。如果那是问题,那么您可以尝试一些更复杂的方法,其中检查值是否已更改以及已看到多少时间值。library(shiny)
library(logging)
basicConfig()
shinyApp(
server = function(input, output, session) {
n <- 2 # How many times you have to see the value to change
interval <- 3000 # Set interval, make it large so we can see what is going on
# We need reactive only for current but it is easier to keep
# all values in one place
values <- reactiveValues(current=0, pending=0, times=0)
observe({
# Invalidate
invalidateLater(interval, session)
# Isolate so we don't trigger execution
# by changing reactive values
isolate({
m <- input$mean
# Slider value is pending and not current
if(m == values$pending && values$current != values$pending) {
# Increment counter
values$times <- values$times + 1
loginfo(paste(values$pending, "has been seen", values$times, "times"))
# We've seen value enough number of times to plot
if(values$times == n) {
loginfo(paste(values$pending, "has been seen", n, "times. Replacing current"))
values$current <- values$pending
}
} else if(m != values$pending) { # We got new pending
values$pending <- m
values$times <- 0
loginfo(paste("New pending", values$pending))
}
})
})
output$plot <- renderPlot({
x <- rnorm(n=1000, mean=values$current, sd=1)
plot(density(x))
})
},
ui = fluidPage(
sliderInput("mean", "Mean:", min = -5, max = 5, value = 0, step= 0.1),
plotOutput("plot")
)
)
关于r - 滑块输入延迟,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/32235525/