在NLTK中,如何遍历已解析的句子以返回名词短语字符串列表?
我有两个目标:
(1)创建名词短语列表,而不是使用'traverse()'方法打印它们。我现在使用Stringio来记录现有travel()方法的输出。这不是一个可接受的解决方案。
(2)对名词短语字符串进行去解析,使:“(np-michael/nnp-jackson/nnp)”变为“michael-jackson”。在NLTK中有没有一个方法可以去解析?
NLTK文档建议使用traverse()来查看名词短语,但是如何捕获递归方法中的“t”,以便生成字符串名词短语列表?
from nltk.tag import pos_tag
def traverse(t):
try:
t.label()
except AttributeError:
return
else:
if t.label() == 'NP': print(t) # or do something else
else:
for child in t:
traverse(child)
def nounPhrase(tagged_sent):
# Tag sentence for part of speech
tagged_sent = pos_tag(sentence.split()) # List of tuples with [(Word, PartOfSpeech)]
# Define several tag patterns
grammar = r"""
NP: {<DT|PP\$>?<JJ>*<NN>} # chunk determiner/possessive, adjectives and noun
{<NNP>+} # chunk sequences of proper nouns
{<NN>+} # chunk consecutive nouns
"""
cp = nltk.RegexpParser(grammar) # Define Parser
SentenceTree = cp.parse(tagged_sent)
NounPhrases = traverse(SentenceTree) # collect Noun Phrase
return(NounPhrases)
sentence = "Michael Jackson likes to eat at McDonalds"
tagged_sent = pos_tag(sentence.split())
NP = nounPhrase(tagged_sent)
print(NP)
目前打印:
(NP迈克尔/NNP杰克逊/NNP)
(NP麦当劳/NNP)
并将“无”存储到NP
最佳答案
def extract_np(psent):
for subtree in psent.subtrees():
if subtree.label() == 'NP':
yield ' '.join(word for word, tag in subtree.leaves())
cp = nltk.RegexpParser(grammar)
parsed_sent = cp.parse(tagged_sent)
for npstr in extract_np(parsed_sent):
print (npstr)
关于python - NLTK:如何遍历名词短语以返回字符串列表?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/33815401/