class LargeNumberPb
{
    Stack s1;
    Stack s2;
    Stack res;
    string first;
    string second;

    public LargeNumberPb()
    {
         first = "10";
         second = "11";
         s1 = new Stack();
         s2 = new Stack();
         res = new Stack();
    }

    public void Fill()
    {
        for (int i = 0; i < first.Length; i++)
        {
            s1.Push(first.Substring(i,1));
        }
        for (int i = 0; i < second.Length; i++)
        {
            s2.Push(second.Substring(i,1));
        }
    }

    public Stack Sum()
    {
        for (int i = 0; i < s.Count; i++)
        {
            res.Push(Convert.ToInt32(s1.Pop()) + Convert.ToInt32(s2.Pop()));
        }
        return res;
    }
}

我想用stack来解决添加大数的问题。但它的工作方式不对,如果两个数字是100和11,那么进位会去哪里?

最佳答案

如果两个数字的位数相等,只需修复sum函数(只处理进位,不测试代码):

public Stack Sum()
{
    int carry = 0;
    int count = s1.Count;
    for (int i = 0; i < count; i++)
    {
        var result = Convert.ToInt32(s1.Pop()) + Convert.ToInt32(s2.Pop())
                     + carry;
        res.Push(result%10);
        carry = (result - result % 10)/10;
    }

    var carryStream = carry.ToString();
    for(int i=carryStream.Length-1;i>=0;i--)
    {
         res.push(Convert.ToInt32(carryStream.Substring(i,1);
    }
    return res;
}

编辑:这是不同长度字符串的编辑版本:
        public Stack Sum()
        {
            int carry = 0;
            int count = Math.Min(s1.Count, s2.Count);
            for (int i = 0; i < count; i++)
            {
                var result = Convert.ToInt32(s1.Pop()) + Convert.ToInt32(s2.Pop())
                             + carry;
                res.Push(result % 10);
                carry = (result - result % 10) / 10;
            }

            var carryStream = carry.ToString();
            var remainedStack = s1.Count > 0 ? s1 : s2;
            carry = 0;
            for (int i = carryStream.Length - 1; i >= 0; i--)
            {
                var result = Convert.ToInt32(carryStream.Substring(i, 1))
             + (remainedStack.Count > 0 ? Convert.ToInt32(remainedStack.Pop()) : 0);
                res.Push(result % 10);
                carry = (result - result % 10) / 10;
            }

            if (remainedStack.Count > 0)
            {
                int remainedCount = remainedStack.Count;
                for (int i = 0; i < remainedStack.Count; i++)
                {
                    var result = carry + Convert.ToInt32(remainedStack.Pop());
                    res.Push(result % 10);
                    carry = (result - result % 10) / 10;
                }

            }

            if (carry != 0)
                res.Push(carry);

            return res;
        }

关于c# - 如何用堆栈增加大数?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/7879158/

10-10 10:34