c - 程式无法运作

我仍然被认为是c语言的初学者，我开始学习文件。我已经建立了一个空白文件。每次我编译这个程序，文件还是空白的。需要帮助！!

    #include <stdio.h>
    #include <stdlib.h>

     int main()
    {
       FILE * x;
       char name[25];

       printf("enter your name: ");
       scanf("%s", &name);

       x = fopen("x1.txt", "w");

       if(x = NULL)
      {
         printf("Unable to open the file");
      }

       else
      {
         fprintf(x, "%s\n", name);

         printf("date has been entered successfully to the file");
         fclose(x);
      }


 return 0;
}

谢谢你

最佳答案

一个文件存在，并包含我的名字，在作出以下变化和重建/运行程序：
（原因见第行注释）
更改：

if(x = NULL)//assignment - as is, this statement will always evaluate
            //to false, as x is assigned to NULL.

致：

if(x == NULL)// comparison - this will test whether x is equal to NULL without changing x.

更改：（这是未填充文件的密钥）

   scanf("%s", &name);//the 'address of' operator: '&' is not needed here.
                      //The symbol 'name' is an array of char, and is
                      //located at the address of the first element of the array.

致：

   scanf("%s", name);//with '&' removed.

或者更好：

   scanf("%24s", name);//'24' will prevent buffer overflows
                       //and guarantee room for NULL termination.

还有一种方法来处理关于not using scanf at all...的评论：

char buffer[25];//create an additional buffer
...
memset(name, 0, 25);//useful in loops (when used) to ensure clean buffers
memset(buffer, 0, 25);
fgets(buffer, 24, stdin);//replace scanf with fgets...
sscanf(buffer, "%24s", name);//..., then analyze input using sscanf
                             //and its expansive list of format specifiers
                             //to handle a wide variety of user input.
                             //In this example, '24' is used to guard
                             //against buffer overflow.

关于最后一种方法，这里有一页detailing the versatility使用sscanf处理用户输入字符串。

关于c - 程式无法运作，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/42866761/