刚才我写了下面提供的代码。我想为以下代码生成输出,但是在运行它时会崩溃,并显示nil
。
class ViewController: UIViewController ,UITableViewDataSource{
var names = [String]()
@IBOutlet weak var tableView: UITableView!
override func viewDidLoad() {
super.viewDidLoad()
title = "\"The List\""
tableView.registerClass(UITableViewCell.self, forCellReuseIdentifier: "Cell")
// Do any additional setup after loading the view, typically from a nib.
}
@IBAction func addName(sender: AnyObject) {
let alert = UIAlertController(title: "New name", message: "Add one new name here", preferredStyle: .Alert)
let saveAction = UIAlertAction(title: "Save", style: .Default, handler: {(action:UIAlertAction) ->Void in
alert.addTextFieldWithConfigurationHandler{(textField:UITextField)->Void in
alert.view.endEditing(true)
let textField = alert.textFields?.last
self.names.append(textField!.text!)
self.tableView.reloadData()
}
})
let cancleAction = UIAlertAction(title: "Cancel", style: .Default, handler: {(action:UIAlertAction) ->Void in
alert.addTextFieldWithConfigurationHandler {(textFiled:UITextField) ->Void in
}
})
alert.addAction(saveAction)
alert.addAction(cancleAction)
self.presentViewController(alert,animated:true,completion:nil)
}
//MARK:-TableViewDataSource
func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return names.count
}
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCellWithIdentifier("Cell")
cell?.textLabel?.text = names[indexPath.row]
return cell!
}
}
如何解决???
最佳答案
在UIALertController
中添加textField的代码:
let alertController = UIAlertController(title: "PlainTextStyle", message: "PlainTextStyle AlertView.", preferredStyle: UIAlertControllerStyle.Alert)
alertController.addTextFieldWithConfigurationHandler { (textField : UITextField) -> Void in
textField.placeholder = "Login"
}
let cancelAction = UIAlertAction(title: "Cancel", style: UIAlertActionStyle.Cancel) { (result : UIAlertAction) -> Void in
print("Cancel")
}
let okAction = UIAlertAction(title: "OK", style: UIAlertActionStyle.Default) { (result : UIAlertAction) -> Void in
print(alertController.textFields?.first?.text)
}
alertController.addAction(cancelAction)
alertController.addAction(okAction)
self.presentViewController(alertController, animated: true, completion: nil)
更新Swift 3.0
let alertController = UIAlertController(title: "PlainTextStyle", message: "PlainTextStyle AlertView.", preferredStyle: UIAlertControllerStyle.alert)
alertController.addTextField { (textField : UITextField) -> Void in
textField.placeholder = "Login"
}
let cancelAction = UIAlertAction(title: "Cancel", style: UIAlertActionStyle.cancel) { (result : UIAlertAction) -> Void in
}
let okAction = UIAlertAction(title: "OK", style: UIAlertActionStyle.default) { (result : UIAlertAction) -> Void in
}
alertController.addAction(cancelAction)
alertController.addAction(okAction)
self.present(alertController, animated: true, completion: nil)
UIALertController中的文本字段:
关于ios - 快速显示alertController中的textField,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/37696485/