我有两张桌子
学生演示:
sid | date | status
--------------------------------
10 | 2013-12-28 | 1
11 | 2013-12-28 | 1
12 | 2013-12-28 | 1
13 | 2013-12-28 | 1
10 | 2013-12-30 | 1
11 | 2013-12-30 | 1
12 | 2013-12-30 | 1
13 | 2013-12-30 | 1
spdemo:
date | status
------------------------
2013-12-28 | cd
2013-12-29 | wd
2013-12-30 | cd
使用查询
SELECT *
FROM `studentdemo`
RIGHT JOIN spdemo
ON spdemo.date = studentdemo.date
WHERE spdemo.date BETWEEN "2013-12-28"
AND "2013-12-30"
得出日期
2013-12-29
的空值:NULL NULL NULL 2013-12-29 WD
可以通过sid获得输出吗?
sid | date | status | date | status
-------------------------------------------------------
10 | null | null | 2013-12-29 | wd
11 | null | null | 2013-12-29 | wd
12 | null | null | 2013-12-29 | wd
13 | null | null | 2013-12-29 | wd
最佳答案
您可以交叉连接以获取所有组合,然后将LEFT JOIN
表添加到该表;
SELECT x.sid, table1.date, table1.status, x.date bdate, table2.status bstatus
FROM (SELECT DISTINCT table1.sid, table2.date
FROM table1 CROSS JOIN table2) x
LEFT JOIN table1 ON x.sid=table1.sid AND x.date = table1.date
LEFT JOIN table2 ON x.date=table2.date
ORDER BY bdate, sid
An SQLfiddle to test with。
关于mysql - 在mysql中加入两个表?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/20840581/