我有一个(Postgres
)查询,其中包含一个常用的group by
子句:
select extract(year from a.created) as Year,a.testscoreid, b.irt_tlevel, count(a.*) as Questions
from asmt.testscores a join asmt.questions b
on a.questionid = b.questionid
where a.answered = True
group by Year,a.testscoreid, b.irt_tlevel
order by Year desc, a.testscoreid
列
b.irt_tlevel
具有值low
、medium
和high
,所有这些结果均为行格式,例如:Year TestScoreId Irt_tlevel Questions
2015 1 Low 2
2015 1 Medium 3
2015 1 High 5
我希望我的结果采用以下格式:
Year TestScoreId Low Medium High TotalQuestions
2015 1 2 3 5 10
任何帮助都将不胜感激。
最佳答案
如果已知irt t t level列中不同值的数目是固定的,则可以使用条件聚合。
select
extract(year from a.created) as Year,
a.testscoreid,
sum(case when b.irt_tlevel = 'Low' then 1 else 0 end) as Low,
sum(case when b.irt_tlevel = 'Medium' then 1 else 0 end) as Medium,
sum(case when b.irt_tlevel = 'High' then 1 else 0 end) as High,
count(*) as Questions
from asmt.testscores a
join asmt.questions b on a.questionid = b.questionid
where a.answered = True
group by Year, a.testscoreid
order by Year desc, a.testscoreid
关于sql - 进行分组依据会导致多列,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/34500598/