我已经从stackoverflow上的另一个用户那里获得了字符串的所有排列的代码,我正在尝试使其在我的网页中起作用。这段代码有什么问题吗?尝试提交单词时,javascript控制台出现错误。错误会短暂闪烁,因此我无法读取。
$(document).ready(function() {
$('form#anagram').submit(function(event) {
function findAllPermutations(str, index, buffer) {
if (typeof str == "string") {
str = str.split("") };
if (typeof index == "undefined") {
index = 0 };
if (typeof buffer == "undefined") {
buffer = [] };
if (index >= str.length) {
return buffer };
for (var i = index; i < str.length; i++) {
buffer.push(ToggleLetters(str, index, i));
}
return FindAllPermutations(str, index + 1, buffer);
}
function ToggleLetters(str, index1, index2) {
if (index1 != index2) {
var temp = str[index1]
str[index1] = str[index2]
str[index2] = temp
};
return str.join("");
}
list = $('input#word').val();
$('#resulttext').append("<p>" + findAllPermutations(list) + "</p>")
event.preventDefault();
});
});
这是HTML:
<!DOCTYPE html>
<html>
<head>
<link href="css/bootstrap.css" rel="stylesheet" type="text/css">
<link href="css/styles.css" rel="stylesheet" type="text/css">
<script src="js/jquery-1.11.1.js"></script>
<script src="js/scripts3.js"></script>
<title>Anagram finder</title>
</head>
<body>
<div class="container">
<div class="band">
<h1>Anagram Finder</h1>
</div>
<form id="anagram">
<div class="form-group">
<label for="word">Your Word</label>
<input id="word" type="text">
</div>
<button type="submit" class="btn">Find!</button>
</form>
<div id="resulttext">
</div>
</div>
</body>
</html>
最佳答案
函数名称中有一个错误,并且由于event.preventDefault()位于函数的末尾,您将无法在刷新页面时看到该错误。
尝试一下:-
<!DOCTYPE html>
<script src="jquery.js"></script>
<title>Anagram finder</title>
</head>
<body>
<script>
$(document).ready(function() {
$('form#anagram').submit(function(event) {
event.preventDefault();
function findAllPermutations(str, index, buffer) {
if (typeof str == "string") {
str = str.split("") };
if (typeof index == "undefined") {
index = 0 };
if (typeof buffer == "undefined") {
buffer = [] };
if (index >= str.length) {
return buffer };
for (var i = index; i < str.length; i++) {
buffer.push(ToggleLetters(str, index, i));
}
return findAllPermutations(str, index + 1, buffer);
}
function ToggleLetters(str, index1, index2) {
if (index1 != index2) {
var temp = str[index1]
str[index1] = str[index2]
str[index2] = temp
};
return str.join("");
}
list = $('input#word').val();
$('#resulttext').append("<p>" + findAllPermutations(list) + "</p>")
});
});
</script>
<div class="container">
<div class="band">
<h1>Anagram Finder</h1>
</div>
<form id="anagram">
<div class="form-group">
<label for="word">Your Word</label>
<input id="word" type="text">
</div>
<button type="submit" class="btn">Find!</button>
</form>
<div id="resulttext">
</div>
</div>
</body>
</html>
关于javascript - 字符串jquery的所有排列,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/24221881/