php - 检索两个SUM(col)JOIN不同值的商

对不起，标题令人困惑，不知道该如何措辞。

我有一个事件表，以及一个关于这些事件的赌注表。我已经获取了每项赛事的总投注额，但我也想获取赔率（aka，一个团队的总数除以另一团队的总数的商）。下注的参与者存储在horse表的data_bets列中。

例如，我想添加以下内容：

SELECT
    SUM(data_bets.amount) WHERE data_bets.horse = data_events.challenger
    /
    SUM(data_bets.amount) WHERE data_bets.horse = data_events.contestant
AS bet_odds

到我下面的现有查询：

SELECT *,
   SUM(data_bets.amount) AS total_pot,
   COUNT(data_bets.member) AS total_bets,
   COUNT(data_votes.member) AS total_votes,
   data_platforms.name AS platform_name, data_platforms.icon AS platform_icon
FROM data_events
   LEFT JOIN data_bets ON data_bets.event=data_events.id
   LEFT JOIN data_votes ON data_votes.content_type=2 AND data_votes.content_id=data_events.id
   LEFT JOIN data_platforms ON data_platforms.id=data_events.platform
WHERE status=1
GROUP BY data_events.id
ORDER BY total_pot DESC

这可能与一个查询有关吗？如果可能的话，我希望同时获取challenger_odds和contestant_odds，如下所示：

SELECT
    SUM(data_bets.amount) WHERE data_bets.horse = data_events.challenger
    /
    SUM(data_bets.amount) WHERE data_bets.horse = data_events.contestant
AS challenger_odds,
    SUM(data_bets.amount) WHERE data_bets.horse = data_events.contestant
    /
    SUM(data_bets.amount) WHERE data_bets.horse = data_events.challenger
AS contestant_odds

最佳答案

使用条件聚合：

SELECT (SUM(CASE WHEN data_bets.horse = data_events.challenger THEN data_bets.amount ELSE 0 END)  /
        SUM(CASE WHEN data_bets.horse = data_events.contestant THEN data_bets.amount END)
       ) as bet_odds

关于php - 检索两个SUM(col)JOIN不同值的商，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/37647666/