c++ - 在opencv中执行dct时出​​错

为什么当我尝试在opencv中实现dct时出​​现以下错误？

Assertion failed (type == CV_32FC1 || type == CV_64FC1) in dct,

这是代码:

#include <cv.h>
#include "opencv2/imgproc/imgproc.hpp"
#include <highgui.h>
#include <iostream>

using namespace cv;
using namespace std;

int main()
{
    Mat image,dimage(image);
       image = imread( "lena.jpg", 1 );

      if( !image.data )
        {
          printf( "No image data \n" );
           return -1;
         }

        namedWindow( "Display Image", CV_WINDOW_AUTOSIZE );
        imshow( "Display Image", image );
        dimage=Mat::zeros(image.rows,image.cols,CV_32F);
        dct(image, dimage, DCT_INVERSE == 0 );

        namedWindow( "DCT Image", CV_WINDOW_AUTOSIZE );
        imshow( "DCT image", dimage );
        waitKey(0);

       return 0;
}

最佳答案

您必须先将图像从uchar转换为float(然后再转换回uchar):

// also please use the c++ headers, not the old c-ones !

#include "opencv2/core/core.hpp"
#include "opencv2/imgproc/imgproc.hpp"
#include "opencv2/highgui/highgui.hpp"

Mat image = imread( "lena.jpg", 0 ); // grayscale

Mat fimage;
image.convertTo(fimage, CV_32F, 1.0/255); // also scale to [0..1] range (not mandatory)

// you're lucky with lena (512x512), for odd sizes, you have to
// pad it to pow2 size, or use dft() instead:
Mat dimage;
dct( fimage, dimage );
// process dimage,
// then same way back:
dct( dimage, dimage, DCT_INVERSE );
dimage.convertTo(image, CV_8U); // maybe scale back to [0..255] range (depending on your processing)

imshow("result",image);
waitKey();

关于c++ - 在opencv中执行dct时出​​错，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/27730534/