mysql - 从GROUP BY获取一天中最大和最小时间的ID行

我不知道怎样才能得到这些信息。
这是我的问题

SELECT
    CAST(reports.report_creation_datetime AS DATE) AS report_date,
    MIN(CAST(reports.report_creation_datetime AS TIME)) AS work_start, <--- I want to get id of this row
    MAX(CAST(reports.report_creation_datetime AS TIME)) AS work_end    <--- and this
FROM       reports
WHERE      reports.report_creation_datetime >= '2016-02-01'
AND        reports.report_creation_datetime < LAST_DAY('2016-02-01') + INTERVAL 1 DAY
GROUP BY   CAST(reports.report_creation_datetime AS DATE)

样本数据

---reports table
report_id     report_creation_datetime
 ------------------------------------
   82           2016-02-01 07:20:00
   80           2016-02-01 10:30:00
   85           2016-02-01 17:00:00
   88           2016-02-02 08:00:00
   87           2016-02-02 16:00:00
   81           2016-02-03 10:50:00

我想得到

---expected result
report_date      work_start      wstart_id     ...
 -------------------------------------------------------
 2016-02-01       07:20:00          82         ...
 2016-02-02       08:00:00          88         ...
 2016-02-03       10:50:00          81         ...
 ...
 2016-02-29       07:30:00          199        ...

我想这样的子查询
其中日期=分钟（日期）
但这是不对的

最佳答案

有两种不同的方法可以做到这一点。您可以在两个子查询中使用join将表返回到自身。您可以使用aggregation。
也许最简单的解决方案是两个相关的子查询：

SELECT
    CAST(r.report_creation_datetime AS DATE) AS report_date,
    MIN(CAST(r.report_creation_datetime AS TIME)) AS work_start,
    (SELECT id FROM reports r2
    WHERE CAST(r.report_creation_datetime AS DATE) = CAST(r2.report_creation_datetime AS DATE)
    ORDER BY r2.report_creation_datetime
    LIMIT 1) work_start_id,
    MAX(CAST(reports.report_creation_datetime AS TIME)) AS work_end,
    (SELECT id FROM reports r3
    WHERE CAST(r.report_creation_datetime AS DATE) = CAST(r3.report_creation_datetime AS DATE)
    ORDER BY r3.report_creation_datetime DESC
    LIMIT 1) work_end_id
FROM       reports r
WHERE      r.report_creation_datetime >= '2016-02-01'
AND        r.report_creation_datetime < LAST_DAY('2016-02-01') + INTERVAL 1 DAY
GROUP BY   CAST(r.report_creation_datetime AS DATE)

这里有一个替代方案，也应该返回领带：

SELECT t.report_date, t.work_start, t.work_end, r1.id minid, r2.id maxid
FROM (
    SELECT
        CAST(reports.report_creation_datetime AS DATE) AS report_date,
        MIN(CAST(reports.report_creation_datetime AS TIME)) AS work_start,
        MAX(CAST(reports.report_creation_datetime AS TIME)) AS work_end
    FROM       reports
    WHERE      reports.report_creation_datetime >= '2016-02-01'
    AND        reports.report_creation_datetime < LAST_DAY('2016-02-01') + INTERVAL 1 DAY
    GROUP BY   CAST(reports.report_creation_datetime AS DATE)
) t
    JOIN reports r1 ON t.report_date = CAST(r1.report_creation_datetime AS DATE) AND t.work_start = CAST(r1.report_creation_datetime AS TIME)
    JOIN reports r2 ON t.report_date = CAST(r2.report_creation_datetime AS DATE) AND t.work_end = CAST(r2.report_creation_datetime AS TIME)

关于mysql - 从GROUP BY获取一天中最大和最小时间的ID行，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/35530821/