public interface INestedInterfaceTest<TChildType>
where TChildType : INestedInterfaceTest<TChildType>
{
List<TChildType> children { get; set; }
}
public abstract class NestedInterfaceTest : INestedInterfaceTest<NestedInterfaceTest>
{
public List<NestedInterfaceTest> children { get; set; }
public TNestedInterface GetNestedInterface<TNestedInterface>()
where TNestedInterface : NestedInterfaceTest, new()
{
return GateWay<TNestedInterface>.GetNestedInterface();
}
}
public class GateWay<TNestedInterface>
where TNestedInterface : class, INestedInterfaceTest<TNestedInterface>, new()
{
public static TNestedInterface GetNestedInterface()
{
return new TNestedInterface();
}
}
抽象类中的GetNestedInterface方法出错。
错误消息是:类型'TNestedInterface'必须可转换为'INestedInterfaceTest',以便在通用类'GateWay'中将其用作参数'TNestedInterface'。
但是...,我的抽象类NestedInterfaceTest实现了INestedInterfaceTest接口。
我在这里想念什么?
在没有递归接口实现的情况下,以下方法可以工作:
public interface INestedInterfaceTest
{
}
public abstract class NestedInterfaceTest : INestedInterfaceTest
{
public List<NestedInterfaceTest> children { get; set; }
public TNestedInterface GetNestedInterface<TNestedInterface>()
where TNestedInterface : NestedInterfaceTest, new()
{
return GateWay<TNestedInterface>.GetNestedInterface();
}
}
public class GateWay<TNestedInterface>
where TNestedInterface : class, INestedInterfaceTest, new()
{
public static TNestedInterface GetNestedInterface()
{
return new TNestedInterface();
}
}
似乎在递归实现中出错。
最佳答案
您缺少对GetNestedInterface<>()
的一般约束。更改为此:
public TNestedInterface GetNestedInterface<TNestedInterface>()
where TNestedInterface :
NestedInterfaceTest,
INestedInterfaceTest<TNestedInterface>, // new
new()
{
return GateWay<TNestedInterface>.GetNestedInterface();
}
注意第二个约束是新的。
关于c# - 类型“TNestedInterface”必须转换为“INestedInterfaceTest”,才能用作参数“TNestedInterface”,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/19234353/