java - 将精良的Class <E>转换为Class <E []>

public abstract class AbstractRESTClientService<E extends IDable<String>>
    implements GenericService<E, String> {


    private Class<E> classType;
    private Class<E[]> classArray;
    private String controllerPath;

    public AbstractRESTClientService(final Class<E> classType,
        final Class<E[]> classArray,
        final String controllerPath) {
            this.classType = classType;
            this.classArray = classArray;
            this.controllerPath = controllerPath;
            this.webService = new GenericWebClientService<E>();
        }

    // ... other methods
}

有没有一种方法可以将classType操纵为classArray，这样我就不需要将classArray作为参数传递了？

最佳答案

我讨厌认为这是最好的方法，但是这就是我的处理方法。

public abstract class AbstractRESTClientService<E extends IDable<String>>
    implements GenericService<E, String> {


private Class<E> classType;
private Class<E[]> classArray;
private String controllerPath;

@SuppressWarnings("unchecked")
public AbstractRESTClientService(final Class<E[]> classArray,
    final String controllerPath) {
        this.classType = (Class<E>) classArray.getComponentType();
        this.classArray = classArray;
        this.controllerPath = controllerPath;
        this.webService = new GenericWebClientService<E>();
    }

    // ... other methods
}

关于java - 将精良的Class <E>转换为Class <E []>，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/36057937/