我想从一个德国论坛上搜罗线索。http://www.musiker-board.de/
实际的不同子函数位于http://www.musiker-board.de/forum
子论坛：musiker-board.de/forum/subflumname
实际的线程有以下地址：musiker-board.de/threads/threadname
我要跟踪所有子流的所有链接并提取其中的所有线程，
但是线程的URL将不再与起始URL匹配。
但是，如果我选择“musiker board.de/”作为开始URL，它不会跟随所有子页面的链接。
代码如下：
allowed_domains = ["musiker-board.de"]
start_urls = ['http://www.musiker-board.de/forum/'
]
rules = (
Rule(SgmlLinkExtractor(allow=[r'forum/\w+']), follow=True),
Rule(SgmlLinkExtractor(allow=[r'threads/\w+']), callback='parse_item'),
)
def parse_item(self, response):
#extract items...
我应该怎么做才能跟踪所有musiker-board.de/forum/subfrom并提取所有musiker-forum.de/threads/threadname？
最佳答案
以下代码（由您的代码片段生成）似乎工作正常：
# -*- coding: utf-8 -*-
import scrapy
from scrapy.spiders import CrawlSpider, Rule
from scrapy.linkextractors import LinkExtractor
class Scrapy1Spider(CrawlSpider):
name = "musiker"
allowed_domains = ["musiker-board.de"]
start_urls = ['http://www.musiker-board.de/forum/'
]
rules = (
Rule(LinkExtractor(allow=[r'forum/\w+']), follow=True),
Rule(LinkExtractor(allow=[r'threads/\w+']), callback='parse_item'),
)
def parse_item(self, response):
self.logger.info('response.url=%s' % response.url)
至少有此输出（已截断）：
INFO: response.url=http://www.musiker-board.de/threads/peavey-ms-412-userthread.271458/
INFO: response.url=http://www.musiker-board.de/threads/peavey-5150-6505-etc-userthread.180295/
INFO: response.url=http://www.musiker-board.de/threads/marshall-ma-serie-user-thread.386428/
INFO: response.url=http://www.musiker-board.de/threads/h-k-metal-master-shredder-user-thread.250846/
INFO: response.url=http://www.musiker-board.de/threads/hughes-und-kettner-grandmeister-user-thread.553487/
INFO: response.url=http://www.musiker-board.de/threads/ibanez-userthread.190547/
INFO: response.url=http://www.musiker-board.de/threads/hughes-kettner-edition-blue-user-thread.209499/page-2
INFO: response.url=http://www.musiker-board.de/threads/fender-prosonic-userthread.239519/
INFO: response.url=http://www.musiker-board.de/threads/fender-prosonic-userthread.239519/page-5
INFO: response.url=http://www.musiker-board.de/threads/engl-steve-morse-signature-e656-user-thread.427802/page-2
INFO: response.url=http://www.musiker-board.de/threads/engl-sovereign-user-thread.136266/page-20
INFO: response.url=http://www.musiker-board.de/threads/engl-steve-morse-signature-e656-user-thread.427802/
INFO: response.url=http://www.musiker-board.de/threads/engl-sovereign-user-thread.136266/page-19
INFO: response.url=http://www.musiker-board.de/threads/engl-sovereign-user-thread.136266/page-18
INFO: response.url=http://www.musiker-board.de/threads/engl-invader-user-thread.248090/page-5
INFO: response.url=http://www.musiker-board.de/threads/engl-sovereign-user-thread.136266/
INFO: response.url=http://www.musiker-board.de/threads/engl-invader-user-thread.248090/page-4
INFO: response.url=http://www.musiker-board.de/threads/engl-invader-user-thread.248090/page-3
INFO: response.url=http://www.musiker-board.de/threads/fender-cybertwin-userthread.305789/
INFO: response.url=http://www.musiker-board.de/threads/fenders-famose-farbwelten.454766/
关于python - Scrapy:使用正则表达式跟踪链接，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/32696774/