我有2个字段的JSON-名称和性别。
如果性别是男性,我想将每个名字都涂成蓝色,如果是女性,我想将它们涂成粉红色。

这是我的代码

ArrayList feedList1 = new ArrayList<HashMap<String, Object>>();


for (int i = 0; i < data.length(); i++) {
    HashMap<String, Object> hm;
    hm = new HashMap<String, Object>();

    hm.put("id", data.getJSONObject(i).getString("id").toString());
    hm.put("gender", data.getJSONObject(i).getString("gender").toString());
    hm.put("name", data.getJSONObject(i).getString("name").toString());
    feedList1.add(hm);
    SimpleAdapter adapter = new SimpleAdapter(feedList.getContext(), feedList1, R.layout.list,
            new String[] {"id","name"}, new int[] { R.id.personId, R.id.personName }){
        @Override
        public void setViewText(TextView v, String text) {
            super.setViewText(v, text);
            if (v.getId() == R.id.personName) {

                if (/* how to get gender of this person*/)
                    v.setTextColor(R.color.female);
                else
                    v.setTextColor(R.color.male);
            }
        }

    };

    feedList.setAdapter(adapter);
    feedList.setChoiceMode(feedList.CHOICE_MODE_SINGLE);
}


请告诉我如何在IF语句中添加性别。

最佳答案

如果不创建自己的自定义适配器,则无法这样做,因此可以覆盖getView。检查以下代码,并使用CustomAdapter代替SimpleAdapter

class CustomAdapter extends SimpleAdapter {

    public CustomAdapter(Context context, List<? extends Map<String, ?>> data, int resource, String[] from, int[] to) {
        super(context, data, resource, from, to);
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View view = super.getView(position, convertView, parent);

        Map<String, Object> item = (Map<String, Object>) getItem(position);
        if ("male".equals(item.get("gender").toString())) {
            view.setBackgroundColor(R.color.male);
        } else {
            view.setBackgroundColor(R.color.female);
        }

        return view;
    }
}

关于java - Android ListView 着色项,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/26979793/

10-09 23:27