就像标题所说的一样,如何将我的discr变量从discr函数放入calcRoots函数中?

// Function calculating roots
bool calcRoots(double coeffs[], int coeffLength, double roots[], int rootLength) {
   if(disc >= 0) {
      roots[rootLength - 1] = ((-(coeffs[coeffLength - 2]) + sqrt(disc)) / (2*(coeffs[coeffLength - coeffLength])));
      roots[rootLength - rootLength] = ((-(coeffs[coeffLength - 2]) - sqrt(disc)) / (2*(coeffs[coeffLength - coeffLength])));
      return true;
   }
   else {
      return false;
   }
}

// Solves the discriminant
double discr(double coeffs[], int coeffLength){
   double disc = (pow(coeffs[coeffLength - 2],2)-4*coeffs[coeffLength - coeffLength]*coeffs[coeffLength - 1]);
   return disc;
}

最佳答案

您没有提到语言,但我想是C ++。
在calcRoots内部,您可以调用discr并将值获取为这样的变量:

double disc = discr(coeffs[], coeffLength);


然后使用变量中的值存储。希望能有所帮助。

关于c++ - 如何将变量从一个函数转换为另一个函数?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/22672364/

10-09 21:31